Python 根据关系确定炼金术顺序

我正在使用一个Flask应用程序，其中我有一个大型的GroupAttention模型，它引用了另一个名为Attendee的模型。我试图请求所有符合特定条件的LargeGroupAttention对象，但我试图按照Attendee模型的列对它们进行排序——这可能吗？以下是两个模型：

""" Attendeee Class """
class Attendee(Base):
    __tablename__ = 'attendee'

    id = Column(Integer, primary_key=True)
    first_name = Column(String(200))
    last_name = Column(String(200))
    year = Column(String(200))
    email = Column(String(100), unique=True)
    dorm = Column(String(100))

    def __init__(self, first_name, last_name, year, email, dorm):
        self.first_name = first_name
        self.last_name = last_name
        self.year = year
        self.email = email
        self.dorm = dorm

    def __repr__(self):
        return '<Attendee %r>' % self.first_name

""" Large Group Attendance Class """
class LargeGroupAttendance(Base):
    __tablename__ = 'large_group_attendance'

    id = Column(Integer, primary_key=True)
    first_time = Column(Integer)

    large_group_id = Column(Integer, ForeignKey('large_group.id'))
    large_group = relationship("LargeGroup", backref=backref('large_group_attendance', order_by=id))

    attendee_id = Column(Integer, ForeignKey('attendee.id'))
    attendee = relationship("Attendee", backref=backref('large_group_attendance', order_by=id))

---

我认为您需要在查询中添加一个连接，类似这样：

.join(LargeGroupAttendance.attendee)

因此，最终查询如下所示：

attendance_records = (db.session.query(LargeGroupAttendance).
    filter_by(large_group_id = event_id).
    join(Attendee, LargeGroupAttendance.attendee).
    order_by(desc(Attendee.first_name))
    )

---

有关更详细的说明，请参见

非常感谢！这正是我需要的！可能重复的

attendance_records = (db.session.query(LargeGroupAttendance).
    filter_by(large_group_id = event_id).
    join(Attendee, LargeGroupAttendance.attendee).
    order_by(desc(Attendee.first_name))
    )