用python解析xml文件的数据

我有以下xml文件：

<address addr="x.x.x.x" addrtype="ipv4"/>
<hostnames>
</hostnames>
<ports><port protocol="tcp" portid="1"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="tcpmux" method="table" conf="3"/></port>
<port protocol="tcp" portid="64623"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="unknown" method="table" conf="3"/></port>
</ports>
<times srtt="621179" rttvar="35357" to="762607"/>
</host>
<host starttime="1418707433" endtime="1418707742"><status state="up" reason="syn-ack" reason_ttl="0"/>
<address addr="y.y.y.y" addrtype="ipv4"/>
<hostnames>
</hostnames>
<ports><port protocol="tcp" portid="1"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="tcpmux" method="table" conf="3"/></port>
<port protocol="tcp" portid="64680"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="unknown" method="table" conf="3"/></port>
</ports>
<times srtt="834906" rttvar="92971" to="1206790"/>
</host>
<host starttime="1418707433" endtime="1418707699"><status state="up" reason="syn-ack" reason_ttl="0"/>
<address addr="w.w.w.w" addrtype="ipv4"/>
<hostnames>
</hostnames>
<ports><extraports state="filtered" count="997">
<extrareasons reason="no-responses" count="997"/>
</extraports>
<port protocol="tcp" portid="25"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="smtp" method="table" conf="3"/></port>
<port protocol="tcp" portid="443"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="https" method="table" conf="3"/></port>
<port protocol="tcp" portid="7443"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="oracleas-https" method="table" conf="3"/></port>
</ports>
<times srtt="690288" rttvar="110249" to="1131284"/>
</host>

但它会把IP的所有信息都返回给我。如何获取每个IP的具体信息

---

我想我应该更改root.findall，但我不知道如何才能做到这一点。

对我来说，这段代码似乎可疑：

        ports=[port.get('portid') for port in root.findall('.//port')]
        state=[port.get('state') for port in root.findall('.//port/state')]
        name=[port.get('name') for port in root.findall('.//port/service')]

在循环内部，您将在整个根节点中搜索“//port…”内容。 看来你需要这个：

        ports=[port.get('portid') for port in host.findall('.//port')]
        state=[port.get('state') for port in host.findall('.//port/state')]
        name=[port.get('name') for port in host.findall('.//port/service')]

---

在循环中，只需将root.findall更改为host.findall：

这会将查找端口、状态和名称的范围限制为每个主机内的端口、状态和名称，而不是整个XML文档中的端口、状态和名称。

通过指定

root.findall('.//port')

再次从文档的根开始，因此返回所有端口

ports=[port.get('portid') for port in host.findall('./ports/port')]

root.findall('.//port')

ports=[port.get('portid') for port in host.findall('./ports/port')]