(builtins.TypeError)SQLite日期类型仅接受Python日期对象作为输入
我尝试了许多在SQLAlchemy对象中插入日期的方法。但这是错误的 我的路线文件:(builtins.TypeError)SQLite日期类型仅接受Python日期对象作为输入,python,json,sqlalchemy,try-catch,Python,Json,Sqlalchemy,Try Catch,我尝试了许多在SQLAlchemy对象中插入日期的方法。但这是错误的 我的路线文件: app.route('/signup', methods=['POST']) def signup(): reply = {} try: data = request.get_json() password_hash = generate_password_hash(data['password']) datelist = data['birthd
app.route('/signup', methods=['POST'])
def signup():
reply = {}
try:
data = request.get_json()
password_hash = generate_password_hash(data['password'])
datelist = data['birthdate'].split('-')
bdate = datetime.date(int(datelist[0]), int(datelist[1]), int(datelist[2]))
new_user = Entities.User(id = uuid.uuid4(), username = data['username'], fullname = data['fullname'], email = data['email'], password_hash = password_hash, birthdate = bdate)
db.session.add(new_user)
db.session.commit()
reply['status'] = "OK"
reply['message'] = ""
except Exception as e:
reply['status'] = "FAIL"
reply['message'] = str(e)
return jsonify(reply)
我的SQLAlchemy用户类:
class User(db.Model):
id = db.Column(db.String(40), unique=True, primary_key=True)
username = db.Column(db.String(25), index=True, unique=True)
fullname = db.Column(db.String(25), index=True)
email = db.Column(db.String(25), index=True, unique=True)
password_hash = db.Column(db.String(128))
imagelink = db.Column(db.String(300), default = "some.url.unspecified.com")
bio = db.Column(db.String(700), default = "No Bio Added")
datejoined = db.Column(db.Date, default = date.today().strftime("%Y-%m-%d"))
birthdate = db.Column(db.String(10))
我的查询的JSON正文:
我正在向本地主机发送此消息<代码>http://127.0.0.1:5001/signup
{
"username":"amandesai01",
"fullname":"Aman Desai",
"password":"xyz123",
"email":"amandesai01@gmail.com",
"birthdate":"2000-10-14"
}
我得到的答复是:
{
"message": "(builtins.TypeError) SQLite Date type only accepts Python date objects as input.\n[SQL: INSERT INTO user (id, username, fullname, email, password_hash, imagelink, bio, datejoined, birthdate) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)]\n[parameters: [{'password_hash': 'pbkdf2:sha256:150000$CPZYKMPJ$b4e0f3a01e17e533a92cd21709b1e4f496f068bd19c8b31fa2723cbbf1ea6beb', 'id': UUID('0e8f6414-27af-4ca9-8e72-a0f4974a0b0d'), 'fullname': 'Aman Desai', 'birthdate': datetime.date(2000, 10, 14), 'email': 'amandesai01@gmail.com', 'username': 'amandesai01'}]]",
"status": "FAIL"
}
错误说明了问题所在。试试这个
datetime
类“生日”
列我不明白他们到底需要哪一个日期对象。我尝试了datetime.date,但没有成功:(
datejoined=db.Column(db.date,default=date.today().strftime(%Y-%m-%d))
有一个有趣的默认值。除非每天重新启动应用程序,default=datetime.date.today()
对于默认值来说是一个错误的选择。默认值应该是日期。今天
本身起作用。从问题和回答来看,很明显,他们在将出生日期作为一个值传递之前已经在转换出生日期,而问题可能是字符串默认值datejoined
datetime.date(2000-10-14)是有效的Python,但引发了一个异常,因为传递1个整数参数1976
不是调用date()
的方法。在编辑答案时,我犯了一些错误。我编辑了it@Kalana你还没有解决Ilja提出的问题。
from datetime import datetime, date
{
"username":"amandesai01",
"fullname":"Aman Desai",
"password":"xyz123",
"email":"amandesai01@gmail.com",
"birthdate": datetime.date(2000-10-14)
}
datejoined = db.Column(db.Date, default = date.today())