PyQT4异步QTcpServer（如何创建事件循环） 试图将C++编写的服务器转换为Python。服务器被写为异步/非阻塞。C++中的工作似乎不想在Python 中为我工作。

我正在使用PyQT4。我读过Python，你必须创建事件循环或类似的东西，任何想法都非常感谢

我应该提到的是，似乎不起作用的是从未调用Class Server中的incomingConnection函数

*干杯

import sys
from PyQt4.QtCore import *
from PyQt4.QtNetwork import *


class Client(QObject):
    def __init__(self, parent=None):
        QObject.__init__(self)
        QThreadPool.globalInstance().setMaxThreadCount(15)

    def SetSocket(self, Descriptor):
        self.socket = QTcpSocket(self)
        self.connect(self.socket, SIGNAL("connected()"), SLOT(self.connected()))
        self.connect(self.socket, SIGNAL("disconnected()"), SLOT(self.disconnected()))
        self.connect(self.socket, SIGNAL("readyRead()"), SLOT(self.readyRead()))

        self.socket.setSocketDescriptor(Descriptor)
        print "Client Connected from IP %s" % self.socket.peerAddress().toString()

    def connected(self):
        print "Client Connected Event"

    def disconnected(self):
        print "Client Disconnected"

    def readyRead(self):
        msg = self.socket.readAll()
        print msg


class Server(QObject):
    def __init__(self, parent=None):
        QObject.__init__(self)

    def incomingConnection(self, handle):
        print "incoming"
        self.client = Client(self)
        self.client.SetSocket(handle)

    def StartServer(self):
        self.server = QTcpServer()
        if self.server.listen(QHostAddress("0.0.0.0"), 8888):
            print "Server is awake"    
        else:
            print "Server couldn't wake up"


def main():
    app = QCoreApplication(sys.argv)
    Server().StartServer()
    sys.exit(app.exec_())

if __name__ == '__main__':
    main()

---

incomingConnection

未被调用，因为调用了

qtcserver

函数的基本实现。由于

incomingConnection

是一个虚拟函数，您只需将您的分配给QTcpServer的incomingConnection属性，如下所示：

class Server(QObject):
    def __init__(self, parent=None):
        QObject.__init__(self)

    def incomingConnection(self, handle):
        print "incoming"
        self.client = Client(self)
        self.client.SetSocket(handle)

    def StartServer(self):
        self.server = QTcpServer()
        self.server.incomingConnection = self.incomingConnection
        if self.server.listen(QHostAddress("0.0.0.0"), 8888):
            print "Server is awake"    
        else:
            print "Server couldn't wake up"

您可以查看PySide的文档，因为它比PyQt更具Python风格，目前仅在此处托管：

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对于这个图书馆来说，情况似乎并非如此；也许您最好使用基本套接字和线程。