python正则表达式查找以数字为中心的子字符串

我有一根绳子。我想将字符串切割成子字符串，其中包括一个数字，其中包含一个单词，每边由（最多）4个单词包围。如果子字符串重叠，则应合并

Sampletext = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated."
re.findall('(\s[*\s]){1,4}\d(\s[*\s]){1,4}', Sampletext)
desired output = ['the way I know 54 how to take praise', 'to take praise for 65 excellent questions 34 thank you for asking']

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重叠匹配：使用Lookaheads

the way I know 54 how to take praise
to take praise for 65 excellent questions 34 thank
for 65 excellent questions 34 thank you for asking

subject = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated."    
for match in re.finditer(r"(?=((?:\b[a-z]+\b ){4}\d+(?: \b[a-z]+\b){4}))", subject, re.IGNORECASE):
    print(match.group(1))

这可以做到：

subject = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated."
for match in re.finditer(r"(?=((?:\b\w+\b ){4}\d+(?: \b\w+\b){4}))", subject):
    print(match.group(1))

什么是单词？

输出取决于您对单词的定义。这里，一句话，我允许数字。这将产生以下输出

输出（允许字中有数字）

选项2：文字中无数字

the way I know 54 how to take praise
to take praise for 65 excellent questions 34 thank
for 65 excellent questions 34 thank you for asking

subject = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated."    
for match in re.finditer(r"(?=((?:\b[a-z]+\b ){4}\d+(?: \b[a-z]+\b){4}))", subject, re.IGNORECASE):
    print(match.group(1))

输出2

the way I know 54 how to take praise

选项3：扩展到四个不间断的非数字字

the way I know 54 how to take praise
to take praise for 65 excellent questions 34 thank
for 65 excellent questions 34 thank you for asking

subject = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated."    
for match in re.finditer(r"(?=((?:\b[a-z]+\b ){4}\d+(?: \b[a-z]+\b){4}))", subject, re.IGNORECASE):
    print(match.group(1))

根据您的评论，此选项将延伸到轴的左侧和右侧，直到匹配四个不间断的非数字字。忽略逗号

subject = "by the way I know 54 how to take praise for 65 excellent questions 34 thank you for asking appreciated. One Two Three Four 55 Extend 66 a b c d AA BB CC DD 71 HH DD, JJ FF"
for match in re.finditer(r"(?=((?:\b[a-z]+[ ,]+){4}(?:\d+ (?:[a-z]+ ){1,3}?)*?\d+.*?(?:[ ,]+[a-z]+){4}))", subject, re.IGNORECASE):
    print(match.group(1))

输出3

the way I know 54 how to take praise
to take praise for 65 excellent questions 34 thank you for asking
One Two Three Four 55 Extend 66 a b c d
AA BB CC DD 71 HH DD, JJ FF

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请见见我如何简化选项3表达式，以便将单词广泛定义为由空格（\S+）包围的非空格（/S+）组。数字是任何包含数字的“单词”。根据你的定义，“单词”也可以与“数字单词”匹配？你说“当然”，但对我来说，在这些情况下，如果你的单词也可以是非数字单词，那么在一个数字单词之外再加上四，意味着什么？对不起，我现在无法理解。如果你需要一个快速的答案，请发布一个新的问题。如果是这样，我建议你参考第一个问题。以后可能有时间，但不确定。：）