如何使用剧作家Python异步打开多个页面？

我想使用Playwright for Python一次打开多个URL。但我正在努力想办法。这来自异步文档：

async def main():
    async with async_playwright() as p:
        for browser_type in [p.chromium, p.firefox, p.webkit]:
            browser = await browser_type.launch()
            page = await browser.newPage()
            await page.goto("https://scrapingant.com/")
            await page.screenshot(path=f"scrapingant-{browser_type.name}.png")
            await browser.close()

asyncio.get_event_loop().run_until_complete(main())

这将按顺序打开每个浏览器类型。如果我想同时做这件事，我该怎么做呢？如果我想用URL列表做类似的事情，我该怎么做呢

我试着这样做：

urls = [
    "https://scrapethissite.com/pages/ajax-javascript/#2015",
    "https://scrapethissite.com/pages/ajax-javascript/#2014",
]
async def main(url):
    async with async_playwright() as p:
        browser = await p.chromium.launch(headless=False)
        page = await browser.newPage()
        await page.goto(url)
        await browser.close()

async def go_to_url():
    tasks = [main(url) for url in urls]
    await asyncio.wait(tasks)

go_to_url()

但这给了我以下错误：

92: RuntimeWarning: coroutine 'go_to_url' was never awaited
  go_to_url()
RuntimeWarning: Enable tracemalloc to get the object allocation traceback

---

我相信您需要使用相同的方法调用您的

go\u to\u url

函数：

asyncio.get\u event\u loop（）。运行\u直到完成（转到\u url（））