Python 如何创建该类对象的数组（列表或dict）？

参考：

有时，使用类似于Pascal“record”或C“struct”的数据类型，将几个命名的数据项捆绑在一起是很有用的。空的类定义可以很好地执行以下操作：

class Employee:
    pass
john = Employee()  # Create an empty employee record
# Fill the fields of the record
john.name = 'John Doe'
john.dept = 'computer lab'
john.salary = 1000

我发现这种存储数据的方法非常有用，我是一个学习python的vb.Net的家伙，在vb中我会去的

Dim x(Mydata.getupperbound(0)) as Employee


and populate it like 
For i as integer = 0 to Mydata.getupperbound(0)
  x(i).name = mydata(i).Name
  x(i).dept = mydata(i).dept
  x(i).salary = mydata(i).salary

next 

问：想在python中使用类似.Net结构的python类执行类似操作吗？如何做到这一点

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感谢您在python中执行此操作的方法是创建一个具有所需属性的类

class Employee:
    def __init__(self, name, dept, salary="100K"):
        self.name = name
        self.dept = dept
        self.salary = salary

emp1 = Employee("Mark", "Sales", "150K")
emp2 = Employee("John", "Engineering")   # Salary is set to default value of 100K

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如果您想进行完整的数据抽象并将数据存储在一个对象中，那么请将类型列表中的名称、部门、薪资设置为，并使用sep函数将这些值添加到列表中

class Employee:

    def __init__(self):
        self.name = []
        self.department = []
        self.salary = []

    def add_data(self, name, dept, salary):
        self.name.append(name)
        self.salary.append(salary)
        self.department.append(dept)


names =['a', 'b', 'c']
depts =['x', 'y', 'z']
salary = [100,200,3000]

x = Employee()

for name, dept, sal in zip(names, depts, salary):
    x.add_data(name, dept, sal)

for name, dept, sal in zip(x.name, x.department, x.salary):
    print(name, dept, sal, sep='\t')

输出

a   x   100
b   y   200
c   z   3000

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如果我正确地阅读了问题标题，那么您拥有Employee类，在第一个列表中被实例化为john，并希望将其转换为dict或list？每个类都已经有一个

\uuuu dict\uuu

属性，您可以访问该属性：

>>> class Employee:
...     pass
...
>>> john = Employee()
>>> john.name = 'John Doe'
>>> john.dept = 'computer lab'
>>> john.salary = 1000
>>>
>>> john.__dict__
{'name': 'John Doe', 'dept': 'computer lab', 'salary': 1000}
>>> john.__dict__['name']
'John Doe'

然后，您可以直接将john转化为dict：

>>> john = john.__dict__
>>> john['name']
'John Doe'

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另请参见：

如果您使用的是Python 3.7+，请完美地填充您的用例：

from dataclasses import dataclass

@dataclass
class Employee:
    name: str
    dept: str
    # Could also be float if that fits better
    # These are just annotations and do not actually control the held data type
    salary: int

实例化它们很简单：

john = Employee('John Doe', 'computers', 1000)
bill = Employee('Billy Joe', 'marketing', 900)

dataclasses

模块还自动实现实例的漂亮打印：

>>>print(john)
Employee(name='John Doe', dept='computers', salary=1000)
>>>print(bill)
Employee(name='Billy Joe', dept='marketing', salary=900)

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python中mydata的格式是什么？ie dict、csv等？@dataclass看起来很棒，谢谢，所以我可以用FOR或WHILE循环来填充它。谢谢