Python 如何允许tkinter窗口多次打开

我正在用python制作一个临时登录系统。目前，如果您输入正确的密码，它会弹出一个新的管理窗口。如果您输入了错误的密码，它会弹出一个显示错误密码的新窗口。如果您退出其中一个窗口，然后再次尝试输入密码，则密码将中断

tkinter.TclError:无法调用“wm”命令：应用程序已被破坏

是否有办法防止这种情况发生，以便如果有人输入错误的密码，他们不需要重新启动应用程序

import tkinter
from tkinter import *

#define root window
root = tkinter.Tk()
root.minsize(width=800, height = 600)
root.maxsize(width=800, height = 600)

#define admin window
admin = tkinter.Tk()
admin.minsize(width=800, height = 600)
admin.maxsize(width=800, height = 600)
admin.withdraw()

#define wrong window
wrong = tkinter.Tk()
wrong.minsize(width=200, height = 100)
wrong.maxsize(width=200, height = 100)
wrong.withdraw()
Label(wrong, text="Sorry that password is incorrect!", font=("Arial", 24), anchor=W, wraplength=180, fg="red").pack()

#Admin sign in Label
areAdmin = Label(root, text="Administrator sign in", font=("Arial", 18))
areAdmin.pack()

#password label and password
passwordLabel = Label(root, text="Password: ", font=("Arial", 12))
passwordLabel.place(x=300, y=30)

#password entry
adminPasswordEntry = Entry(root)
adminPasswordEntry.place(x=385, y=32.5)

#function for button
def getEnteredPassword():
    enteredPassword = adminPasswordEntry.get()
    if enteredPassword == password:
        admin.deiconify()
    else:
        wrong.deiconify()

#enter button for password
passwordEnterButton = Button(root, text="Enter", width=20, command=getEnteredPassword)
passwordEnterButton.place(x=335, y=60)


mainloop()

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我不太清楚，但是我可以修复你的代码，我希望这是一个正确的修复

创建

Toplevel

窗口而不是

Tk

。这些是对话框窗口，而不是必须唯一的

Tk

窗口。相同的外观和感觉，相同的方法

在需要时和每次创建窗口。否则，使用close小工具关闭它们会破坏它们

修正了密码，输入错误或正确的密码，您可以多次输入，而不会崩溃：

import tkinter
from tkinter import *

password="good"

#define root window
root = tkinter.Tk()
root.minsize(width=800, height = 600)
root.maxsize(width=800, height = 600)



#Admin sign in Label
areAdmin = Label(root, text="Administrator sign in", font=("Arial", 18))
areAdmin.pack()

#password label and password
passwordLabel = Label(root, text="Password: ", font=("Arial", 12))
passwordLabel.place(x=300, y=30)

#password entry
adminPasswordEntry = Entry(root)
adminPasswordEntry.place(x=385, y=32.5)

#function for button
def getEnteredPassword():
    enteredPassword = adminPasswordEntry.get()
    if enteredPassword == password:
        admin = tkinter.Toplevel()
        admin.minsize(width=800, height = 600)
        admin.maxsize(width=800, height = 600)
        #admin.withdraw()
    else:
        wrong = tkinter.Toplevel()
        wrong.minsize(width=200, height = 100)
        wrong.maxsize(width=200, height = 100)
        Label(wrong, text="Sorry that password is incorrect!", font=("Arial", 24), anchor=W, wraplength=180, fg="red").pack()


#enter button for password
passwordEnterButton = Button(root, text="Enter", width=20, command=getEnteredPassword)
passwordEnterButton.place(x=335, y=60)


mainloop()

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有趣的是，我开始在if语句中编码admin，然后决定不太做，我想我应该这么做，谢谢你的回答。什么是错误的=None和admin=None？