为字典中的同一个键创建多个值（Python）

我目前有两个不同的数组，我希望将它们存储在字典中相同的索引号下，例如：

字典（期望结果）： 索引键：

array([[   0],
       [   1],
       [   2],
       ...,
       [1997],
       [1998],
       [1999]])

array([[50.],
       [42.],
       [46.],
       ...,
       [46.],
       [60.],
       [46.]])

array([[-1.95364833, -2.3406949 , -1.78136408, ...,  2.20188999,
         2.44994974,  1.11205757],
       [-2.23099494, -2.56195164, -1.7833544 , ...,  2.1898737 ,
         2.55687737,  1.91171312],
       [-1.91742587, -2.31495118, -2.00310111, ...,  2.10471678,
         2.31442952,  1.38450444],
       ...,
       [-2.17547345, -2.25906157, -1.8122977 , ...,  2.04136801,
         2.66251564,  1.73665702],
       [-2.25692463, -2.60385466, -1.83966994, ...,  2.11042762,
         2.52533793,  1.98603952],
       [-1.93614006, -2.27099538, -2.02284527, ...,  2.20629144,
         2.48619676,  1.36994064]])>

第1个值：

array([[   0],
       [   1],
       [   2],
       ...,
       [1997],
       [1998],
       [1999]])

array([[50.],
       [42.],
       [46.],
       ...,
       [46.],
       [60.],
       [46.]])

array([[-1.95364833, -2.3406949 , -1.78136408, ...,  2.20188999,
         2.44994974,  1.11205757],
       [-2.23099494, -2.56195164, -1.7833544 , ...,  2.1898737 ,
         2.55687737,  1.91171312],
       [-1.91742587, -2.31495118, -2.00310111, ...,  2.10471678,
         2.31442952,  1.38450444],
       ...,
       [-2.17547345, -2.25906157, -1.8122977 , ...,  2.04136801,
         2.66251564,  1.73665702],
       [-2.25692463, -2.60385466, -1.83966994, ...,  2.11042762,
         2.52533793,  1.98603952],
       [-1.93614006, -2.27099538, -2.02284527, ...,  2.20629144,
         2.48619676,  1.36994064]])>

第2个值：

array([[   0],
       [   1],
       [   2],
       ...,
       [1997],
       [1998],
       [1999]])

array([[50.],
       [42.],
       [46.],
       ...,
       [46.],
       [60.],
       [46.]])

array([[-1.95364833, -2.3406949 , -1.78136408, ...,  2.20188999,
         2.44994974,  1.11205757],
       [-2.23099494, -2.56195164, -1.7833544 , ...,  2.1898737 ,
         2.55687737,  1.91171312],
       [-1.91742587, -2.31495118, -2.00310111, ...,  2.10471678,
         2.31442952,  1.38450444],
       ...,
       [-2.17547345, -2.25906157, -1.8122977 , ...,  2.04136801,
         2.66251564,  1.73665702],
       [-2.25692463, -2.60385466, -1.83966994, ...,  2.11042762,
         2.52533793,  1.98603952],
       [-1.93614006, -2.27099538, -2.02284527, ...,  2.20629144,
         2.48619676,  1.36994064]])>

当前尝试 但我一直在犯这样的错误：

TypeError: unhashable type: 'numpy.ndarray'

---

下面是一个简单方法的示例：

arr1 = [1, 2, 3]
arr2 = [10, 20, 30]
my_dict = {}

for index, (value1, value2) in enumerate(zip(arr1, arr2)):
    my_dict[index] = [value1, value2]

---

请尝试

zip（索引数组、嵌入、临时数组）

删除额外的for循环并使用

defaultdict（列表）

抱歉，我不确定您是如何引用它的？会是这样吗？embedded_dict={}for i in zip（index_array，embeddedings_array，temp_array）：embedded_dict（i）谢谢，这绝对是我想要的：）我得到了这样的东西，{0:[array（[-1.95364833，-2.3406949，-1.78136408，…，2.20188999，2.449974，1.11205757]），array（[50.]），1:[array]([-2.23099494，-2.56195164，-1.7833544，…，2.1898737，2.55687737，1.91171312]），数组（[42.]）]