Python 将价格绘制为非零体积值的水平线

我的代码：

import matplotlib.pyplot as plt
plt.style.use('seaborn-ticks')
import pandas as pd
import numpy as np

path = 'C:\\File\\Data.txt'
df = pd.read_csv(path, sep=",")
df.columns = ['Date','Time','Price','volume']
df = df[df.Date == '08/02/2019'].reset_index(drop=True)
df['Volume'] = np.where((df.volume/1000) < 60, 0, (df.volume/1000))

df.plot('Time','Price')

dff = df[df.Volume > 60].reset_index(drop=True)
dff = dff[['Date','Time','Price','Volume']]
print(dff)

plt.subplots_adjust(left=0.05, bottom=0.05, right=0.95, top=0.95, wspace=None, hspace=None)
plt.show()

我想根据下图将此表的价格绘制为垂直线。任何帮助

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根据你的形象，我认为你指的是水平线。无论哪种方式，它都非常简单，Pyplot有/内置。在你的情况下，试试类似的方法

plt.hlines(dff['Price'], '08/02/2019', '09/02/2019') 

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添加了行，但没有得到输出。您是在plt.show之前添加的吗？根本没有输出？x轴的值是多少？它是df数据帧的时间

plt.hlines(dff['Price'], '08/02/2019', '09/02/2019') 

import matplotlib.pyplot as plt
import pandas as pd
import numpy as np

path = 'File.txt'
df = pd.read_csv(path, sep=",")
df.columns = ['Date','Time','Price','volume']
df = df[df.Date == '05/02/2019'].reset_index(drop=True)
df['Volume'] = np.where((df.volume/7500) < 39, 0, (df.volume/7500))
df["Time"] = pd.to_datetime(df['Time'])

df.plot(x="Time",y='Price', rot=0)

plt.title("Date: " + str(df['Date'].iloc[0]))

dff = df[df.Volume > 39].reset_index(drop=True)
dff = dff[['Date','Time','Price','Volume']]
print(dff)

dict = dff.to_dict('index')
for x in range(0, len(dict)):
    plt.axhline(y=dict[x]['Price'],linewidth=2, color='blue')

plt.subplots_adjust(left=0.05, bottom=0.06, right=0.95, top=0.96, wspace=None, hspace=None)
plt.show()