Python 输入为'；句子'；，如何返回显示最频繁的元素

第一个函数计算字符串的字符数

def character_count(sentence):
    characters = {}
    for char in sentence:
        if char in characters:
            characters[char] = characters[char] + 1
        else: 
            characters[char] = 1
    return characters

第二个函数确定最常见的字符，并通过在上一个helper函数中建立的字符[char]来标识最常出现的字符

def most_common_character(sentence):
    chars = character_count(sentence)
    most_common = ""
    max_times = 0


    for curr_char in chars:
        if chars[curr_char] > max_times:
            most_common = curr_char
            max_times = chars[curr_char]
    return most_common

---

你实际上不需要改变任何事情！您的代码将按原样使用列表（变量名只是会产生误导）。试试看：

输出：

'a'

---

这将适用于具有任何类型的可散列元素（数字、字符串、字符等）的列表。

为什么不简单地使用Python提供的内容呢

>>> from collections import Counter
>>> sentence = "This is such a beautiful day, isn't it"
>>> c = Counter(sentence).most_common(3)
>>> c
[(' ', 7), ('i', 5), ('s', 4)]

如果您真的想逐字进行并避免空格，请执行以下操作：

>>> from collections import Counter
>>> sentence = "This is such a beautiful day, isn't it"
>>> res = Counter(sentence.replace(' ', ''))
>>> res.most_common(1)
[('i', 5)]

---

目前什么是

句子

？字符串？只需使用

计数器

>>> from collections import Counter
>>> sentence = "This is such a beautiful day, isn't it"
>>> res = Counter(sentence.replace(' ', ''))
>>> res.most_common(1)
[('i', 5)]