Python：在字符串中查找单词

我想在下面这样的字符串中查找单词：

kkk="I do not like that car."

if "like" in kkk:
    print("like")
elif "dislike" in kkk:
    print("dislike")
elif "hate" in kkk:
    print("hate")
elif "cool" in kkk:
    print("cool")

但由于我的代码很长，我希望将其缩短：

if "like" in kkk or "dislike" in kkk or "hate" in kkk or "cool" in kkk:
    #print "like" 
    #unable to do it this way

然后我试着用另一种方法，但没有成功：

a=["like","dislike","hate","cool"]

if any(x in kkk for x in a):
    print(x)
    #NameError: name 'x' is not defined

---

使用遍历列表的for循环。并将变量名更改为更有意义的名称

kkk="I do not like that car."
wordlist =["like","dislike","hate","cool"]
for word in wordlist:
    if word in kkk:
         print(word)

试试这个：

>>> kkk="I do not like that car."
>>> a=["like","dislike","hate","cool"]
>>> print(*[x for x in a if x in kkk])
like

此列表理解与以下内容相同：

for x in a:
    if x in kkk:
        print(x)

---

any

不会返回找到的单词；最好的选择可能是

next

：

keywords = ["like", "dislike", "hate", "cool"]
sentence = "I do not like that car."

try:
    word = next(k for k in keywords if k in sentence)
    print(word)
except StopIteration:
    print('Not found')

如果您不想处理异常而改为获取

None

：

word = next((k for k in keywords if k in sentence), None)

---

另一种方法是使用集合：

kkk="I do not like that car."
kkk_split = kkk.split(' ')
print({'like', 'dislike', 'hate', 'cool'}.intersection(kkk_split))

---

对于您的情况，关键字中的

会导致冲突结果。例如，下面的代码段：

sentence = "I do dislike that car."
opinion = ["like","dislike","hate","cool"]
for word in opinion:
    if word in sentence:
        print(word)

打印
喜欢的
和
不喜欢的
。相反，您可以使用正则表达式零宽度字边界来获得准确的结果，如下所示：

import re

sentence = "I do dislike that car."
opinion = ["like","dislike","hate","cool"]
for word in opinion:
    if re.search(r'\b'+word+r'\b', sentence):
        print(word)

只打印
不喜欢
。
变量名的选择有点奇怪和不寻常…为什么不为a中的x使用一个简单的
for循环
-->
：如果kkk中的x:print（x）
？请注意，
拆分
并设置交集不一定会产生与

@deceze中的

相同的结果，这是怎么回事？
'like'与
{'like'}。交集（{'He'，'likes'，'cars'）
。的确，它不适用于子字符串，但我认为作者要求的是完整的单词