Python 从元组列表中提取元素
我有一个表单中的输出Python 从元组列表中提取元素,python,python-3.x,list,tuples,nltk,Python,Python 3.x,List,Tuples,Nltk,我有一个表单中的输出 [('the', 1334), ('and', 919), ('a', 615), ('to', 560), ('i', 519), ('in', 317), ('he', 299), ('they', 287), ('was', 277), ('it', 276), ('of', 267), ('on', 214), ('you', 210), ('went', 206)] 我的问题是如何选择给定单词的值。例如,我的函数如下所示: def un
[('the', 1334),
('and', 919),
('a', 615),
('to', 560),
('i', 519),
('in', 317),
('he', 299),
('they', 287),
('was', 277),
('it', 276),
('of', 267),
('on', 214),
('you', 210),
('went', 206)]
我的问题是如何选择给定单词的值。例如,我的函数如下所示:
def unigram(word):
u = [' '.join(w).lower() for w in train_corrected] # I want to change train corrected to a list of sentences so I can lower every character
u = ' '.join(u) # makes the list of sentences into one giant string
u = nltk.word_tokenize(u) # converts the giant string back into a list of single word elements
freq = Counter(u).most_common() # https://docs.python.org/3/library/collections.html
return freq # we only want the result of the word we input into our function not the entire dict of freq
我想回去说
unigram('the') # The output of which would be 1334 from the list of tuples
有人能给我指出正确的方向吗?我将使用列表:
def unigram(word):
return [x[1] for x in train_corrected if x[0] == word][0]
然后像这样打电话:
print(unigram('the'))
下面的代码块可以帮助您。Required_string是您希望根据问题中显示的元组列表为其关联值的字符串
Required_string = 'the'
For I in output:
If I[0] == required_string:
Print(I[1])
使用@Patrick Artner的答案达到了预期的结果。谢谢你,伙计
def unigram(word):
u = [' '.join(w).lower() for w in train_corrected] # I want to change train corrected to a list of sentences so I can lower every character
u = ' '.join(u) # makes the list of sentences into one giant string
u = nltk.word_tokenize(u) # converts the giant string back into a list of single word elements
freq = Counter(u).most_common() # https://docs.python.org/3/library/collections.html
return return Counter(u).get(word,0) # we only want the result of the word we input into our function not the entire dict of freq
print(unigram('the')) # output = 1334 as expected
返回计数器(u)。获取(word,0)
-如果您多次查询此项,则应缓存计数器结果。谢谢Patrick,这是有效的。嗨,Wasif,谢谢,但它不起作用。我收到“列表索引超出范围”错误