python中通过队列传输文件对象
我有一个多处理任务,它处理输入数据并将结果写入临时文件(供以后使用)。但是,当我尝试通过队列将文件句柄传输到父进程时,它失败了(不会引发异常,但队列仍然为空)python中通过队列传输文件对象,python,multiprocessing,temporary-files,Python,Multiprocessing,Temporary Files,我有一个多处理任务,它处理输入数据并将结果写入临时文件(供以后使用)。但是,当我尝试通过队列将文件句柄传输到父进程时,它失败了(不会引发异常,但队列仍然为空) 有人知道解决方案吗?如果在辅助函数中调用read并在其工作后关闭,则保持打开状态的文件似乎是导致问题的原因: from multiprocessing import Process, Queue def worker(i,queue): my_tmp_file = tempfile.NamedTemporaryFile()
有人知道解决方案吗?如果在辅助函数中调用read并在其工作后关闭,则保持打开状态的文件似乎是导致问题的原因:
from multiprocessing import Process, Queue
def worker(i,queue):
my_tmp_file = tempfile.NamedTemporaryFile()
my_tmp_file.write(bytes('Hello world #{}'.format(i), 'utf-8'))
my_tmp_file.seek(0)
queue.put(my_tmp_file.read())
my_tmp_file.close()
q = Queue()
processes = [Process(target=worker, args=(i, q)) for i in range(16)]
for p in processes:
p.start()
for p in processes:
p.join()
while q.qsize():
out = q.get()
print(out)
如果试图在不读取的情况下关闭文件对象,则会出现类型错误:无法将“\u io.FileIO”对象
序列化为不可点击的\u io.FileIO
对象
根据您要执行的操作,将.name放入队列并将delete设置为False,然后重新打开文件可能会有所帮助:
import multiprocessing, tempfile
def worker(i):
with tempfile.NamedTemporaryFile(delete=False) as my_tmp_file:
my_tmp_file.write(bytes('Hello world #{}'.format(i), 'utf-8'))
my_tmp_file.seek(0)
queue.put(my_tmp_file.name)
queue = multiprocessing.Queue()
print('Writing...')
proc = []
for i in range(16):
proc.append(multiprocessing.Process(target = worker, args = (i, )))
proc[i].start()
for p in proc:
p.join()
print('Reading...')
my_strings = []
while True:
try:
tmp_file = queue.get_nowait()
except Exception as e:
print('All data are read. Queue is now empty')
break
with open(tmp_file) as f:
my_strings.append(f)
但是您仍然需要重新打开该文件,因此不确定是否会有任何好处
import multiprocessing, tempfile
def worker(i):
with tempfile.NamedTemporaryFile(delete=False) as my_tmp_file:
my_tmp_file.write(bytes('Hello world #{}'.format(i), 'utf-8'))
my_tmp_file.seek(0)
queue.put(my_tmp_file.name)
queue = multiprocessing.Queue()
print('Writing...')
proc = []
for i in range(16):
proc.append(multiprocessing.Process(target = worker, args = (i, )))
proc[i].start()
for p in proc:
p.join()
print('Reading...')
my_strings = []
while True:
try:
tmp_file = queue.get_nowait()
except Exception as e:
print('All data are read. Queue is now empty')
break
with open(tmp_file) as f:
my_strings.append(f)