Python Scrape论坛为每个帖子提供标题
我对网页抓取和Python都是新手。我想在论坛的URL上搜索每篇帖子的标题,然后用下面的标题中的一个创建一篇新帖子。我想收到一封带有该帖子链接的邮件 通过搜索Python Scrape论坛为每个帖子提供标题,python,web-scraping,Python,Web Scraping,我对网页抓取和Python都是新手。我想在论坛的URL上搜索每篇帖子的标题,然后用下面的标题中的一个创建一篇新帖子。我想收到一封带有该帖子链接的邮件 通过搜索div structItem标题,我收到了1页上的23条帖子。但是当我想打印每篇文章的文本时,我只收到打印(键入(first_result.Text))和打印(键入(first_result)) 搜索标题 # Jeti_DS_16 = soup.find_all(text="Jeti DS 16") #
div structItem标题
,我收到了1页上的23条帖子。但是当我想打印每篇文章的文本时,我只收到打印(键入(first_result.Text))和打印(键入(first_result))
搜索标题
# Jeti_DS_16 = soup.find_all(text="Jeti DS 16")
# Jeti_DS_16_v2 = soup.find_all(text="Jeti DS 16 2")
# Jeti_DC_16 = soup.find_all(text="Jeti DC 16")
# Jeti_DC_16_v2 = soup.find_all(text="Jeti DC 16 2")
代码
from requests import get
from bs4 import BeautifulSoup
import re
import smtplib
import time
import lxml
URL = 'https://www.rc-network.de/forums/biete-rc-elektronik-zubeh%C3%B6r.135/'
headers = {
"User-Agent": 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/79.0.3945.79 Safari/537.36'}
def checkForSearchItem():
response = get(URL)
# print(response.text[:500])
# page = requests.get(URL, headers=headers)
# page = requests.get(URL, headers=headers).text
# page = requests.get(URL).text
# page = requests.get(URL)
soup = BeautifulSoup(response.content, "lxml")
# soup = BeautifulSoup(page.content, "html.parser")
# soup = BeautifulSoup(page.text, "html.parser")
search_for_class = soup.find_all(
'div', class_='structItem-title')
# search_for_main = soup.find_all(
# 'div', class_="structItemContainer-group js-threadList")
# Jeti_DS_16 = soup.find_all(text="Jeti DS 16")
# Jeti_DS_16_v2 = soup.find_all(text="Jeti DS 16 2")
# Jeti_DC_16 = soup.find_all(text="Jeti DC 16")
# Jeti_DC_16_v2 = soup.find_all(text="Jeti DC 16 2")
# if(Jeti_DC_16, Jeti_DC_16_v2, Jeti_DS_16, Jeti_DS_16_v2):
# send_mail()
# print('Die Nummer {0} {1} {2} {3} wurden gezogen'.format(
# Jeti_DC_16, Jeti_DC_16_v2, Jeti_DS_16, Jeti_DS_16_v2))
print(type(search_for_class))
print(len(search_for_class))
first_result = search_for_class[0]
# print(type(first_result.h3))
# print(type(first_result.div.a.text))
# print(type(first_result.a.text))
# print(type(first_result.p.text))
# print(type(first_result.name.text))
# print(type(first_result.title))
print(type(first_result))
print(type(first_result.text))
# print(soup.div)
# def send_mail():
# server_ssl = smtplib.SMTP_SSL('smtp.gmail.com', 465)
# server_ssl.ehlo()
# # server.starttls()
# # server.ehlo()
# server_ssl.login('Secure@gmail.com', 'SecurePassword')
# subject = 'Es gibt ein neuer Post im RC-Network auf deine gespeicherte Anfragen. Sieh in dir an{Link to Post}'
# body = 'Sieh es dir an Link: https://www.rc-network.de/forums/biete-rc-elektronik-zubeh%C3%B6r.135/'
# msg = f"Subject: {subject}\n\n{body}"
# emails = ["Secure@gmx.de"]
# server_ssl.sendmail(
# 'Secure@gmail.com',
# emails,
# msg
# )
# print('e-Mail wurde versendet!')
# server_ssl.quit
while(True):
checkForSearchItem()
time.sleep(600)
# time.sleep(86400)
当您想要打印文本时,您不需要type()。只需查看变量的类型(int,str,…)。如果没有type(),我可以很好地打印文本。这意味着,在打印语句上,而不是:
打印(键入(第一个结果文本))
写下:
打印(第一个结果文本)
我希望这就是你的问题所在,我可以帮助你。
当您需要post的URI时,必须在post div中获取a标记并从中提取您的URI,如下所示:
def checkForSearchItem():
response=get(URL)
汤=美汤(response.content,“lxml”)
posts=soup.find_all('div',class='structItem-title')
在职人员:
a_tag=post.find_all('a')[0]#div内的a-tag
link=a_标记。获取('href')#a标记内的href
url=f'https://www.rc-network.de{link}#完整URI,因为“link”看起来像/threads/sensoren-von-graupner.11835933/
打印(post.text)
打印(url)
我真傻,谢谢。你能帮我一下吗,如果有一篇文章有这样的标题,我该如何获取链接?我用URI功能编辑了这篇文章