python中两个十六进制字符串的异或

我有两个字符串值与char和hex等价。如何对这两个字符串进行异或运算，以使结果的格式为\x00\x01\x

其中： String1和String2与相应的ASCII值相等

输入：

我使用下面的方法来查找XOR值

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我想你想的是：

String1 = "ABC"
String2 = "\x72\x61\x74"
result = "".join(chr(c1 ^ c2) for c1, c2 in zip(map(ord, String1), map(ord, String2)))
print(result)
# prints "3#7"

或者，如果要打印十六进制表示，可以：

String1 = "ABC"
String2 = "\x72\x61\x74"
result = "".join("\\x{:02x}".format(c1 ^ c2) for c1, c2 in zip(map(ord, String1), map(ord, String2)))
print(result)
# prints "\x33\x23\x37"

hex(ord('A')) ^ '\x72' = ??
hex(ord('B')) ^ '\x61' = ??
hex(ord('C')) ^ '\x74' = ??

String1 = "ABC"
String2 = "\x72\x61\x74"
result = "".join(chr(c1 ^ c2) for c1, c2 in zip(map(ord, String1), map(ord, String2)))
print(result)
# prints "3#7"

String1 = "ABC"
String2 = "\x72\x61\x74"
result = "".join("\\x{:02x}".format(c1 ^ c2) for c1, c2 in zip(map(ord, String1), map(ord, String2)))
print(result)
# prints "\x33\x23\x37"