Python:类似quartz的事件调度程序

Python:类似quartz的事件调度程序,python,Python,我正在为我的python项目寻找类似java中的quartz的事件调度器 请给我推荐一些好的Python调度程序 我的要求 1) 间隔一段时间后向用户发送电子邮件或短信 谢谢 对于任务来说可能是一种过度杀伤力,也可能是quartz: @celery.task def sendmail(from_addr, to_addrs, msg): "send mail here" sendmail.apply_async(args, countdown=n) # send email in `n

我正在为我的python项目寻找类似java中的quartz的事件调度器

请给我推荐一些好的Python调度程序

我的要求

1) 间隔一段时间后向用户发送电子邮件或短信

谢谢

对于任务来说可能是一种过度杀伤力,也可能是
quartz

@celery.task
def sendmail(from_addr, to_addrs, msg):
    "send mail here"

sendmail.apply_async(args, countdown=n) # send email in `n` seconds
也许是你想要的

例如:

from apscheduler.scheduler import Scheduler

sched = Scheduler()

@sched.interval_schedule(hours=3)
def some_job():
    print "Decorated job"

sched.configure(options_from_ini_file)
sched.start()

一个简单的解决方案是:

from aqcron import At
from time import sleep
from datetime import datetime

# Event scheduling
event_1 = At( second=5 )
event_2 = At( second=[0,20,40] )

while True:
    now = datetime.now()

    # Event check
    if now in event_1: print "event_1"
    if now in event_2: print "event_2"

    sleep(1)
aqcron.At类为:

# aqcron.py

class At(object):
    def __init__(self, year=None,    month=None,
                 day=None,     weekday=None,
                 hour=None,    minute=None,
                 second=None):
        loc = locals()
        loc.pop("self")
        self.at = dict((k, v) for k, v in loc.iteritems() if v != None)

    def __contains__(self, now):
        for k in self.at.keys():
            try:
                if not getattr(now, k) in self.at[k]: return False
            except TypeError:
                if self.at[k] != getattr(now, k): return False
        return True

@塞巴斯蒂安发送邮件不仅仅是我的任务,它可以像发送短信一样