Python:类似quartz的事件调度程序
我正在为我的python项目寻找类似java中的quartz的事件调度器 请给我推荐一些好的Python调度程序 我的要求 1) 间隔一段时间后向用户发送电子邮件或短信 谢谢 对于任务来说可能是一种过度杀伤力,也可能是Python:类似quartz的事件调度程序,python,Python,我正在为我的python项目寻找类似java中的quartz的事件调度器 请给我推荐一些好的Python调度程序 我的要求 1) 间隔一段时间后向用户发送电子邮件或短信 谢谢 对于任务来说可能是一种过度杀伤力,也可能是quartz: @celery.task def sendmail(from_addr, to_addrs, msg): "send mail here" sendmail.apply_async(args, countdown=n) # send email in `n
quartz
:
@celery.task
def sendmail(from_addr, to_addrs, msg):
"send mail here"
sendmail.apply_async(args, countdown=n) # send email in `n` seconds
也许是你想要的
例如:
from apscheduler.scheduler import Scheduler
sched = Scheduler()
@sched.interval_schedule(hours=3)
def some_job():
print "Decorated job"
sched.configure(options_from_ini_file)
sched.start()
一个简单的解决方案是:
from aqcron import At
from time import sleep
from datetime import datetime
# Event scheduling
event_1 = At( second=5 )
event_2 = At( second=[0,20,40] )
while True:
now = datetime.now()
# Event check
if now in event_1: print "event_1"
if now in event_2: print "event_2"
sleep(1)
aqcron.At类为:
# aqcron.py
class At(object):
def __init__(self, year=None, month=None,
day=None, weekday=None,
hour=None, minute=None,
second=None):
loc = locals()
loc.pop("self")
self.at = dict((k, v) for k, v in loc.iteritems() if v != None)
def __contains__(self, now):
for k in self.at.keys():
try:
if not getattr(now, k) in self.at[k]: return False
except TypeError:
if self.at[k] != getattr(now, k): return False
return True
@塞巴斯蒂安发送邮件不仅仅是我的任务,它可以像发送短信一样