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是否可以在Python中执行glmm?_Python_Spss_Data Analysis - Fatal编程技术网

是否可以在Python中执行glmm?

是否可以在Python中执行glmm?,python,spss,data-analysis,Python,Spss,Data Analysis,是否可以在Python中进行glmm(如SPSS中的GENLINMIXED分析)? 我是statsmodels的超级粉丝,但这个库似乎不支持glmm。。。还有其他选择吗 -编辑- 决定用R和r2py来做 def RunAnalyseMLMlogit(dataset, outcomevars, meeneemvars, randintercept, randslope): from rpy2.robjects import pandas2ri from rpy2.robjects

是否可以在Python中进行glmm(如SPSS中的GENLINMIXED分析)? 我是statsmodels的超级粉丝,但这个库似乎不支持glmm。。。还有其他选择吗

-编辑-

决定用R和r2py来做

def RunAnalyseMLMlogit(dataset, outcomevars, meeneemvars, randintercept, randslope):

    from rpy2.robjects import pandas2ri
    from rpy2.robjects.packages import importr
    base = importr('base')
    stats = importr('stats')
    lme4 = importr('lme4')

    #data
    with SavReaderNp(dataset) as reader_np:
        array = reader_np.to_structured_array()

    df = pd.DataFrame(array)

    variabelen = ' '.join(outcomevars) + ' ~ ' + '+'.join(meeneemvars)
    randintercept2 = ['(1|'+i+')' for i in randintercept]
    intercept = '+'.join(randintercept2)
    randslope2 = ['(1+'+meeneemvars[0]+'|'+i+')' for i in randslope]
    slope = ' '.join(randslope2)

    pandas2ri.activate()
    r_df = pandas2ri.py2ri(df)

    #model
    #random intercepts + random slopes
    if len(randslope) > 0:
        formula = variabelen + '+' + intercept + '+' + slope

    #only random intercepts
    else:
        formula = variabelen + '+' + intercept

    model = lme4.glmer(formula, data=r_df, family= 'binomial')
    resultaat = base.summary(model).rx2('coefficients')
    uitkomst = base.summary(model)

    return uitkomst
根据(不可否认,不是最近的)帖子,在Python中运行glmms仍然没有一个很好的解决方案。但是,如果您只是在寻找一个免费(而且更灵活!)的替代方案,而不是在SPSS中运行测试,那么请查看针对R的lme4包。您甚至可以使用rpy2之类的包,直接从Python调用R,但这可能有点问题。

这正是我所做的:)。