如何将代码块集群到级别（Python）

!！我正在尝试用Python构建一个小游戏来猜测一个范围内的随机数。代码将随机选择1,20之间的数字，并要求用户猜3次

我需要帮助将下面的代码块聚集到一个级别（比如级别0）。如果玩家能够正确猜测，则玩家将进入下一级别（级别1）

我需要进一步的帮助，把1级范围的条件改为1,30

import random

secretNumber = random.randint(1,20)
print(" I am thinking of a number between 1 and 20.")

#Ask the player to guess 3 times.
for guessTaken in range(1,4):
    print("Take a guess. ")
    guess1 = int(input())
    if guess < secretNumber:
        print("Your guess is too low")
    elif guess > secretNumber:
        print("Your guess is too high")
    else:
        break

if guess == secretNumber:
    print("Good job! you guessed my number in " + str(guessTaken) + " guesses! Move onto the next level")
else:
    print("Nope. The number I was thinking of was " + str(secretNumber))

secretNumber1 = random.randint(1,30)
print(" Welcome to level 1 I am thinking of a number between 1 and 30.")
for guessTaken1 in range(1,4)
    guess = int(input())
    print("Take a guess. ")
    guess1 = int(input())
    if guess1 < secretNumber1:
    print("Your guess is too low")
    elif guess1 > secretNumber:
        print("Your guess is too high")
    else:
        break

if guess == secretNumber1
    print("Good job! you guessed my number in " + str(guessTaken) + " guesses! Move onto the next level")
else:
    print("Nope. The number I was thinking of was " + str(secretNumber1))

随机导入
secretNumber=random.randint（1,20）
打印（“我想到的是一个介于1和20之间的数字。”）
#让玩家猜3次。
对于在范围（1,4）内进行的猜测：
打印（“猜猜看”）
猜测1=int（输入（））
如果guess秘密编号：
打印（“您的猜测太高”）
其他：
打破
如果guess==secretNumber：
打印（“干得好！你在“+str（猜）+”猜中猜到了我的号码！进入下一个级别”）
其他：
打印（“不，我想的数字是”+str（secretNumber））
secretNumber1=random.randint（1,30）
打印（“欢迎来到级别1，我想到的是一个介于1和30之间的数字。”）
对于范围（1,4）内的猜测1
guess=int（输入（））
打印（“猜猜看”）
猜测1=int（输入（））
如果猜测1秘籍编号：
打印（“您的猜测太高”）
其他：
打破
如果guess==secretNumber1
打印（“干得好！你在“+str（猜）+”猜中猜到了我的号码！进入下一个级别”）
其他：
打印（“不，我想的数字是”+str（secretNumber1））

这将起作用：

import random

def guess_number(max_number):
    print(" I am thinking of a number between 1 and {0}.".format(max_number))
    secret_number = random.randint(1, max_number)

    for guess_taken in range(1,4):
        print("Take a guess. ")
        guess = int(input())
        if guess < secret_number:
            print("Your guess is too low")
        elif guess > secret_number:
            print("You guess is too high")
        else:
            return (True, guess_taken)

    return (False, secret_number)

level = 1
for max_number in range(10, 30, 5):
    print("Current level: {0}".format(level))
    guessed = guess_number(max_number)
    if guessed[0]:
        print("Good job! you guessed my number in " + str(guessed[1]) + " guesses!")
    else:
        print("Nope. The number I was thinking of was " + str(guessed[1]))
        print ("Game over!")
        break
    level += 1

---

您在哪里尝试实现这一新功能？如果玩家在游戏结束时错过3次？您显然需要重新创建您的

secretNumber

，并重新启动循环以请求输入，那么你对哪一个有意见？@cricket\u 007我在重新启动循环时遇到了问题pycharm@DanIonescu是的，如果他们猜错了三次，游戏就结束了，他们会说“不，我想的号码是”+str（secretNumber）谢谢，这真是奇迹！仅对范围（10，30，5）中的最大值进行评论，这是否意味着它将在每个级别增加5，直到达到最大范围30？

Current level: 1
I am thinking of a number between 1 and 10.
Take a guess. 
6
You guess is too high
Take a guess. 
3
Your guess is too low
Take a guess. 
5
Good job! you guessed my number in 3 guesses!
Current level: 2
I am thinking of a number between 1 and 15.
Take a guess. 
7
Your guess is too low
Take a guess. 
10
Your guess is too low
Take a guess. 
13
You guess is too high
Take a guess. 
12
You guess is too high
Nope. The number I was thinking of was 11
Game over!