如何在R数据帧中用数字替换字符值？

我有一个数据集，其中包含两个正确/不正确值的变量很少 我想用1替换所有正确的，用零替换不正确的

变量的数据类型为字符。我尝试了gsub并更换了不起作用的部件。有人能帮我吗

---

df[]将其转换为逻辑，并将逻辑转换为数字
TRUE
始终等于1，而
FALSE
0

a <- c('Correct', 'Incorrect', 'Correct')

sapply(a=='Correct', as.numeric)

[1] 1 0 1

a您可以将列转换为因子，然后再转换为数值，而无需指定条件

#Create data frame

> df <- data.frame(a = c("correct", "correct", "correct"), 
                   b = c("incorrect", "correct", "incorrect") )
> df
        a         b
1 correct incorrect
2 correct   correct
3 correct incorrect

#Convert character columns to numeric using apply:
> df2 <- as.data.frame(apply(df,2,function(L){as.numeric(as.factor(L))}))
> df2
  a b
1 1 2
2 1 1
3 1 2

#创建数据帧
>df-df
a b
1纠正错误
2正确的
3纠正错误
#使用“应用”将字符列转换为数字：
>df2 df2
a b
1 1 2
2 1 1
3 1 2
您是否尝试过
ifelse
df <- data.frame(
  x = c("correct", "correct", "correct", "incorrect", "incorrect", "incorrect"), 
  y = c("correct", "correct", "correct", "incorrect", "correct", "incorrect"), 
  z = c("correct", "incorrect", "correct", "correct", "incorrect", "correct")
)

a <- c('Correct', 'Incorrect', 'Correct')

sapply(a=='Correct', as.numeric)

[1] 1 0 1

df <- data.frame(a=c('Correct', 'Incorrect', 'Correct'), b=c('Correct', 'Incorrect', 'Incorrect'))

df

          a         b
1   Correct   Correct
2 Incorrect Incorrect
3   Correct Incorrect

matrix(sapply(df=='Correct', as.numeric), ncol = ncol(df))

     [,1] [,2]
[1,]    1    1
[2,]    0    0
[3,]    1    0

#Create data frame

> df <- data.frame(a = c("correct", "correct", "correct"), 
                   b = c("incorrect", "correct", "incorrect") )
> df
        a         b
1 correct incorrect
2 correct   correct
3 correct incorrect

#Convert character columns to numeric using apply:
> df2 <- as.data.frame(apply(df,2,function(L){as.numeric(as.factor(L))}))
> df2
  a b
1 1 2
2 1 1
3 1 2