在R中为ggplot2轴标签优雅地创建序列字符串
我试图用年份标记ggplot,但每月保留3个记号,因此需要:在R中为ggplot2轴标签优雅地创建序列字符串,r,ggplot2,R,Ggplot2,我试图用年份标记ggplot,但每月保留3个记号,因此需要: labels = c(0,"","","", 12,"","","", 24,"","","", 36...) 稍微整洁的是: labels = c(0,rep("",3),12,rep("",3),24,rep("",3),36...) 必须能够通过编程方式创建此功能 gsub("," , ",'','',''," ,"0,12,24,36" ) 很接近,但我唯一能解决的实际问题是 labels=c() for (i in 0
labels = c(0,"","","", 12,"","","", 24,"","","", 36...)
稍微整洁的是:
labels = c(0,rep("",3),12,rep("",3),24,rep("",3),36...)
必须能够通过编程方式创建此功能
gsub("," , ",'','',''," ,"0,12,24,36" )
很接近,但我唯一能解决的实际问题是
labels=c()
for (i in 0:3){ labels<-c(labels,i*12,rep("",3)) }
labels=c()
对于(0:3中的i){labels这将创建10年的序列(40个条目)
lbls我会使用seq
创建一个向量,并使用模运算符(%%
)来清空我不想要的条目
# Some data
df <- data.frame( x=seq(0,36) , y = rnorm(37) )
# Make quarterly labels
lab <- seq(0,36,by=3)
# Blank everything that is not evenly divisible by 12 months
lab[ lab %% 12 > 0 ] <- ""
# Plot
ggplot( df , aes(x,y) ) + geom_point() +
scale_x_continuous( breaks = seq(0,36,by=3) , labels = lab )
#一些数据
df我认为你的解决方案看起来很优雅。你也可以做lappy
:unlist(lappy(seq(0,40,12),c,rep(“,3))
ggplot2:::交错(字母[1:3],”,“,”,”)
# Some data
df <- data.frame( x=seq(0,36) , y = rnorm(37) )
# Make quarterly labels
lab <- seq(0,36,by=3)
# Blank everything that is not evenly divisible by 12 months
lab[ lab %% 12 > 0 ] <- ""
# Plot
ggplot( df , aes(x,y) ) + geom_point() +
scale_x_continuous( breaks = seq(0,36,by=3) , labels = lab )