R-使用多个标识符匹配值(当查找ID的顺序是随机的时)
我的问题是这个问题的后续问题。我在这里提出一个新问题,因为这与上一个问题大不相同 假设我有以下两个数据集:R-使用多个标识符匹配值(当查找ID的顺序是随机的时),r,data-manipulation,data-cleaning,R,Data Manipulation,Data Cleaning,我的问题是这个问题的后续问题。我在这里提出一个新问题,因为这与上一个问题大不相同 假设我有以下两个数据集: df1 = data.frame(PersonId1=c(1,2,3,4,5,6,7,8,9,10,1),PersonId2=c(11,12,13,14,15,16,17,18,19,20,11), Played_together = c(1,0,0,1,1,0,0,0,1,0,1), Event=c(1,1,1,1,2,2,2,2,2,2,2),
df1 = data.frame(PersonId1=c(1,2,3,4,5,6,7,8,9,10,1),PersonId2=c(11,12,13,14,15,16,17,18,19,20,11),
Played_together = c(1,0,0,1,1,0,0,0,1,0,1),
Event=c(1,1,1,1,2,2,2,2,2,2,2),
Utility=c(20,-2,-5,10,30,2,1,.5,50,-1,60))
这看起来像:
PersonId1 PersonId2 Played_together Event Utility
1 1 11 1 1 20.0
2 2 12 0 1 -2.0
3 3 13 0 1 -5.0
4 4 14 1 1 10.0
5 5 15 1 2 30.0
6 6 16 0 2 2.0
7 7 17 0 2 1.0
8 8 18 0 2 0.5
9 9 19 1 2 50.0
10 10 20 0 2 -1.0
11 1 11 1 2 60.0
这看起来像:
PersonId1 PersonId2 Played_together Event Utility
1 11 1 1 1 25
2 15 5 1 2 36
3 9 19 1 2 51
4 1 11 1 2 64
我想做以下工作:在df2中查找每一对(在每个事件中,对于一起玩的=1),并将其与df1中的观察结果进行匹配。如果匹配,则在df1中创建一个新列,称为“来自df2的实用程序”。它不是,放0
我面临的挑战来自这样一个事实,即df1和df2中的人员顺序不一致。例如,在df1第1行中,对于事件==1和一起玩=1,我们看到:personid1=1和personid2=11,而在df2第1行中,我有personid1=11和personid2=1,对于事件==1和一起玩=1。因此,两者是相同的。我想从df2中获取实用程序的值,并将其放在df1中的一个新列中。如果没有匹配项,则输入0
最终数据帧应如下所示:
PersonId1 PersonId2 Played_together Event Utility Utility_from_df2
1 1 11 1 1 20.0 25
2 2 12 0 1 -2.0 0
3 3 13 0 1 -5.0 0
4 4 14 1 1 10.0 0
5 5 15 1 2 30.0 36
6 6 16 0 2 2.0 0
7 7 17 0 2 1.0 0
8 8 18 0 2 0.5 0
9 9 19 1 2 50.0 51
10 10 20 0 2 -1.0 0
11 1 11 1 2 60.0 64
非常感谢。使用
dplyr
和数据。表
:
df2 = data.frame(PersonId1=c(11,15,9,1),PersonId2=c(1,5,19,11),
Played_together = c(1,1,1,1),
Event=c(1,2,2,2),
Utility=c(25,36,51,64)) # you had missed adding Utility in your ques
library(data.table)
library(dplyr)
df3 <- copy(df2)
colnames(df2) <- c("PersonId2", "PersonId1", "Played_together", "Event", "Utility")
setDT(df2)
df2 <- df2[, c("PersonId2", "PersonId1", "Utility", "Event")]
df3 <- df3[, c("PersonId2", "PersonId1", "Utility", "Event")]
df <- left_join(df1, df2, c("PersonId2", "PersonId1", "Event"))
df <- left_join(df, df3, by = c("PersonId2", "PersonId1", "Event"))
setDT(df)
df[, Utility_from_df2 := ifelse(is.na(Utility), Utility.y, ifelse(is.na(Utility.y), Utility, 0))]
df[is.na(df)] <- 0
df[, c("Utility.y", "Utility") := NULL]
setnames(df, "Utility.x", "Utility")
df2 = data.frame(PersonId1=c(11,15,9,1),PersonId2=c(1,5,19,11),
Played_together = c(1,1,1,1),
Event=c(1,2,2,2),
Utility=c(25,36,51,64)) # you had missed adding Utility in your ques
library(data.table)
library(dplyr)
df3 <- copy(df2)
colnames(df2) <- c("PersonId2", "PersonId1", "Played_together", "Event", "Utility")
setDT(df2)
df2 <- df2[, c("PersonId2", "PersonId1", "Utility", "Event")]
df3 <- df3[, c("PersonId2", "PersonId1", "Utility", "Event")]
df <- left_join(df1, df2, c("PersonId2", "PersonId1", "Event"))
df <- left_join(df, df3, by = c("PersonId2", "PersonId1", "Event"))
setDT(df)
df[, Utility_from_df2 := ifelse(is.na(Utility), Utility.y, ifelse(is.na(Utility.y), Utility, 0))]
df[is.na(df)] <- 0
df[, c("Utility.y", "Utility") := NULL]
setnames(df, "Utility.x", "Utility")
PersonId1 PersonId2 Played_together Event Utility Utility_from_df2
1: 1 11 1 1 20.0 25
2: 2 12 0 1 -2.0 0
3: 3 13 0 1 -5.0 0
4: 4 14 1 1 10.0 0
5: 5 15 1 2 30.0 36
6: 6 16 0 2 2.0 0
7: 7 17 0 2 1.0 0
8: 8 18 0 2 0.5 0
9: 9 19 1 2 50.0 51
10: 10 20 0 2 -1.0 0
11: 1 11 1 2 60.0 64