Regex 在Scala-Spark中删除文本中的标点符号

这是我的一个数据示例：

case time (especially it's purse), read manual care, follow care instructions make stays waterproof -- example, inspect rubber seals doors (especially battery/memory card door open time) 
xm "life support" picture . flip part bit flimsy guessing won't long . sound great altec speaker dock it! chance back base (xm3020) . traveling bag connect laptop extra speaker . amount paid ($25).

我希望删除除点（.）之外的所有标点符号，并删除长度为

的单词，例如，我的预期输出为：

case time especially its purse read manual care follow care instructions . make stays waterproof example inspect rubber seals doors especially batterymemory card door open time
life support picture . flip part bit flimsy guessing wont long . sound great altec speaker dock chance back base xm3020 . traveling bag connect laptop extra speaker . amount paid $25 .

这应该在Scala中实现，
我试过：

replaceAll( """\\W\s""", "")
replaceAll(""""[^a-zA-Z\.]""", "")

但是效果不好，有人能帮我吗？
这个怎么样：

replaceAll("(\\(|\\)|'|/", "")

然后，您只需使用|添加更多要删除的标点符号，并确保使用双反斜杠转义（and）等字符即可。
您可以尝试按如下方式过滤字符串：

val example = "Hey there! It's me, myself and I."
example.filterNot(x => x == ',' || x == '!' || x == 'm')
 res3: String = Hey there It's e yself and I.

试试这个，它会起作用的：

val str = """
  |case time (especially it's purse), read manual care, follow care instructions make stays waterproof -- example, inspect rubber seals doors (especially battery/memory card door open time) 
  |xm "life support" picture . flip part bit flimsy guessing won't long . sound great altec speaker dock it! chance back base (xm3020) . traveling bag connect laptop extra speaker . amount paid ($25).
  """.stripMargin('|')

println(str)
val pat = """[^\w\s\.\$]"""
val pat2 = """\s\w{2}\s"""
println(str.replaceAll(pat, "").replaceAll(pat2, ""))

输出：

case time especially its purse read manual care follow care instructions make stays waterproof  example inspect rubber seals doors especially batterymemory card door open time 
life support picture . flip part bit flimsy guessing wont long . sound great altec speaker dockchance back base xm3020 . traveling bag connect laptop extra speaker . amount paid $25.

查看regex javadoc（），我们看到标点符号的字符类是
\p{Punct}
，我们可以使用
[a-z&&[^def]]
从字符类中删除字符。从那时起，很容易定义一个正则表达式，该正则表达式将删除除点以外的所有标点：

s.replaceAll("""[\p{Punct}&&[^.]]""", "")

删除大小为
$25
的单词有一个特殊字符，您尚未删除该字符。如果使用第二种模式，您可能希望用“”替换以保留空白。按照当前模式，“狗先生猫”变成“狗猫”。
s.replaceAll("""\b\p{IsLetter}{1,2}\b""")

s.replaceAll("""([\p{Punct}&&[^.]]|\b\p{IsLetter}{1,2}\b)\s*""", "")

s.replaceAll("""([?.!:]|\b\p{IsLetter}{1,2}\b)\s*""", "")

s.replaceAll("""([\p{Punct}&&[^.$]]|\b\p{IsLetter}{1,2}\b)\s*""", "")