Ruby 如何从另一个方法中访问两个方法？

我正在为Odin项目的Ruby编程课程创建一个caesar密码，我的代码已经达到了这样的程度：我有一个方法可以接受一个单词和一个移位值，并使用相应的哈希键和值返回加密的单词。我还有另一种方法，它把一个句子分成一个数组，每个数组包含一个单独的单词。我想做的是将这两种方法结合起来，这样当你输入一个句子时，单词被分成一个数组，然后数组的每个部分都用移位值加密，然后数组中加密的单词被打印回句子形式

以下是我目前的代码：

  "a" => 1,
  "b" => 2,
  "c" => 3,
  "d" => 4,
  "e" => 5,
  "f" => 6,
  "g" => 7,
  "h" => 8,
  "i" => 9,
  "j" => 10,
  "k" => 11,
  "l" => 12,
  "m" => 13,
  "n" => 14,
  "o" => 15,
  "p" => 16,
  "q" => 17,
  "r" => 18,
  "s" => 19,
  "t" => 20,
  "u" => 21,
  "v" => 22,
  "w" => 23,
  "x" => 24,
  "y" => 25,
  "z" => 26,
}```

```#multi letter caesar_cipher
def word_cipher(word, shift)
   word.split(//).each {|letter| print @cipher.key(@cipher[letter]+ shift)}
end

> word_cipher("kittens", 2)
=> mkvvgpu

#split sentence string into an array of words
def sentence_array(sentence)
  sentence.split.each { |word| print word.split }
end 

>sentence_array("Look at all of these kittens")
=>["Look"]["at"]["all"]["of"]["these"]["kittens"]

到目前为止，我的解决方案是什么

def caesar_cipher(input, shift)
  sentence_array(input) = words
  words.split(//).each {|letter| print @cipher.key(@cipher[letter]+ shift)}
end

caesar_cipher("I love kittens", 2)

这是我第一次在这里发帖，所以如果我在解释任何事情时做得不好，我很抱歉，但任何帮助都将不胜感激

---

谢谢

您必须稍微修改方法：

#multi letter caesar_cipher
def word_cipher(word, shift)
  output = ''
  word.split(//).each {|letter| output << @cipher.key(@cipher[letter]+ shift)}
  output
end

def sentence_array(sentence)
  sentence.split
end 

#multi letter caesar_cipher
def caesar_cipher(input, shift)
  output = ""
  words = sentence_array(input)
  words.each do |word|
    output << word_cipher(word.downcase, shift)
    output << " " unless word == words.last 
  end
  output.capitalize
end

puts caesar_cipher("I love kittens", 2)

#多字母凯撒密码
def word_密码（word，shift）
输出=“”
split（/）。我在散列名称上方的每个{字母|输出都是@cipher