Ruby如何删除数组中的数组？

我有：

在我的控制台中：

@pakker[0] = 6

@number = [1, 2, 3, 4, 5, 6]

(1..@pakker[0]).map {|i| @number.map{|d| d}.combination(i).to_a}

如何删除阵列中的所有这些阵列

我尝试过扁平化：

=> [1, 2, 3, 4, 5, 6, [1, 2], [1, 3], [1, 4], [1, 5], [1, 6], etc. 

---

必须有更好的方法，但如果a是上述结果：

<r[0]).map {|i| @number.map{|d| d}.combination(i).to_a}.flatten(1)
=> [[1], [2], [3], [4], [5], [6], [1, 2], [1, 3], [1, 4], [1, 5], [1, 6], [2, 3]
, [2, 4], [2, 5], [2, 6], [3, 4], [3, 5], [3, 6], [4, 5], [4, 6], [5, 6], [1, 2,
 3], [1, 2, 4], [1, 2, 5], [1, 2, 6], [1, 3, 4], [1, 3, 5], [1, 3, 6], [1, 4, 5]
, [1, 4, 6], [1, 5, 6], [2, 3, 4], [2, 3, 5], [2, 3, 6], [2, 4, 5], [2, 4, 6], [
2, 5, 6], [3, 4, 5], [3, 4, 6], [3, 5, 6], [4, 5, 6], [1, 2, 3, 4], [1, 2, 3, 5]
, [1, 2, 3, 6], [1, 2, 4, 5], [1, 2, 4, 6], [1, 2, 5, 6], [1, 3, 4, 5], [1, 3, 4
, 6], [1, 3, 5, 6], [1, 4, 5, 6], [2, 3, 4, 5], [2, 3, 4, 6], [2, 3, 5, 6], [2,
4, 5, 6], [3, 4, 5, 6], [1, 2, 3, 4, 5], [1, 2, 3, 4, 6], [1, 2, 3, 5, 6], [1, 2
, 4, 5, 6], [1, 3, 4, 5, 6], [2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 6]]
irb(main):197:0>

此外，我认为以下内容相当于您的组合创建删除了内部映射：

---

不完全确定。

正在查找[this？][1][1]：@steenslag不完全确定，在收集惰性枚举后，您仍然需要删除一级数组。归根结底，这是同一件事，尽管它假设您实际上在寻找OP的帖子中提到的一个powerset，但并没有说明n必然等于数组的长度。当然，它可以修改为将n作为参数，并巧妙地包装了功能。

<r[0]).map {|i| @number.map{|d| d}.combination(i).to_a}.flatten(1)
=> [[1], [2], [3], [4], [5], [6], [1, 2], [1, 3], [1, 4], [1, 5], [1, 6], [2, 3]
, [2, 4], [2, 5], [2, 6], [3, 4], [3, 5], [3, 6], [4, 5], [4, 6], [5, 6], [1, 2,
 3], [1, 2, 4], [1, 2, 5], [1, 2, 6], [1, 3, 4], [1, 3, 5], [1, 3, 6], [1, 4, 5]
, [1, 4, 6], [1, 5, 6], [2, 3, 4], [2, 3, 5], [2, 3, 6], [2, 4, 5], [2, 4, 6], [
2, 5, 6], [3, 4, 5], [3, 4, 6], [3, 5, 6], [4, 5, 6], [1, 2, 3, 4], [1, 2, 3, 5]
, [1, 2, 3, 6], [1, 2, 4, 5], [1, 2, 4, 6], [1, 2, 5, 6], [1, 3, 4, 5], [1, 3, 4
, 6], [1, 3, 5, 6], [1, 4, 5, 6], [2, 3, 4, 5], [2, 3, 4, 6], [2, 3, 5, 6], [2,
4, 5, 6], [3, 4, 5, 6], [1, 2, 3, 4, 5], [1, 2, 3, 4, 6], [1, 2, 3, 5, 6], [1, 2
, 4, 5, 6], [1, 3, 4, 5, 6], [2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 6]]
irb(main):197:0>

a.flatten(1).collect { |arr| arr.size == 1 ? arr[0] : arr }

(1..6).map { |i| number.map { |d| d }.combination(i) }