Rx java rxjava-如何从包含整数列表的可观测数据流构建整数流

给定一个如下所示的对象：

class Products {
    ArrayList<Integer> numbers;

    public Products(ArrayList<Integer> numbers){}
        this.numbers = numbers;
    }
}

---

您可以将

concatMap（）

与

Observable.from（Iterable）

ArrayList<Integer> numbers1 = new ArrayList();
numbers1.add(23432);
numbers1.add(5555); 
numbers1.add(323423);
Products products1 = new Products(numbers1);
ArrayList<Integer> numbers2 = new ArrayList();
numbers2.add(234222);
numbers2.add(55665); 
numbers2.add(3278663);
Products products2 = new Products(numbers2);
ArrayList<Integer> numbers3 = new ArrayList();
numbers3.add(266622);
numbers3.add(52225); 
numbers3.add(7763);
Products products3 = new Products(numbers3);

23432,5555,323423,234222,55665,3278663,266622,52225,7763

Observable.just(products1, product2, product3)
          .concatMap(product -> Observable.from(product.numbers))
          ...