Shell awk不检查Station是否正确显示输出中的所有打印行

我正在尝试编写以下代码，但awk没有正确检查if语句

#!/bin/bash

sqlplus -S username/pwd << EOF

SET ECHO off;
Set FEEDBACK off;
SET TRIMSPOOL on;
SET TAB off;
SET TERMOUT OFF;
set HEADSEP off;
SET HEADING on;
SET LINESIZE 1000;
SET WRAP off;
set serveroutput off;

SPOOL /tmp/sql_output.xls
select  * from (
select  PROCESS_SRC_STATUS_IND,PROCESS_RUN_TIME_ID,PROCESS_ID from      raptore.tb_process_prod c 
where PROCESS_ID in (116)
order by PROCESS_CREATE_DTM desc
)
where rownum=1

spool off
exit;
EOF

awk '{

if ( $1 == "C")
then
    print "Job J4051 has successfully run for date " $2 

elif ($1 == "P")
then
    print "Job J4051 is pending for date " $2 

elif ($1 == "F")
then
    print "Job J4051 is failed for date " $2

}' /tempt/sql_output.xls

#/bin/bash
sqlplus-S username/pwd在
awk的
if
子句中没有
then

语法应该如下所示

awk '
    {

    if(conditional-expression1)
        action1;
    else if(conditional-expression2)
        action2;
    else if(conditional-expression3)
        action3;
        .
        .
    else
        action n;
    }
   '

awk '{
            if ( $1 == "C")
                print "Job J4051 has successfully run for date " $2 
       else if ( $1 == "P" )
                print "Job J4051 is pending for date " $2 
       else if ( $1 == "F" )
                print "Job J4051 is failed for date " $2
     }
    '  infile


如果条件表达式1为true，则action1将为true
表演
如果conditional-expression1为false，则conditional-expression2为false
将被检查，如果为真，将执行并继续执行操作2
这样地。如果不存在以下情况，则将执行最后一个else部分：
条件表达式为true

修改如下

awk '
    {

    if(conditional-expression1)
        action1;
    else if(conditional-expression2)
        action2;
    else if(conditional-expression3)
        action3;
        .
        .
    else
        action n;
    }
   '

awk '{
            if ( $1 == "C")
                print "Job J4051 has successfully run for date " $2 
       else if ( $1 == "P" )
                print "Job J4051 is pending for date " $2 
       else if ( $1 == "F" )
                print "Job J4051 is failed for date " $2
     }
    '  infile

将提供一个更惯用的
awk
版本

 $ awk '$1=="C"{text="Job J4051 has successfully run for date"} 
        $1=="P"{text=...} 
        ... 
        {print text, $2}' file

您是否尝试打印
$1
？他的价值是什么？也许你不需要使用awk。。您应该使用标准bash
if
statement它使用awk读取sql查询的输出…normal if else无法工作我想我需要将输出值分配给一个变量，因此我使用awkelse if抛出语法错误awk:cmd。行：7:else如果（$1==“P”）awk:cmd。第7行：^语法错误awk:cmd。行：11:else如果（$1==“F”）awk:cmd。第11行：^语法错误请再次检查