Shell 对CSV文件的一列进行排序，导致1123出现在232之前

具体问题-坏标题 我正在尝试对一组CSV数据进行排序，如-

2014/06/04 13:19:06.970,1124,Post Request,200,OK,text,true,,782,1,0
2014/06/04 13:18:27.241,237,Post Request,200,OK,text,true,,303,1,0
2014/06/04 13:12:15.973,2224,Post Request,200,OK,text,true,,1551,1,0
2014/06/04 13:12:31.365,238,Post Request,204,No Content,,true,,237,1,0
2014/06/04 13:12:29.892,1429,Post Request,204,No Content,,true,,237,1,0

使用-

sort -t"," -k2,3

结果是

2014/06/04 13:19:06.970,1124,Post Request,200,OK,text,true,,782,1,0
2014/06/04 13:18:27.241,1429,Post Request,200,OK,text,true,,303,1,0
2014/06/04 13:12:15.973,2224,Post Request,200,OK,text,true,,1551,1,0
2014/06/04 13:12:31.365,237,Post Request,204,No Content,,true,,237,1,0
2014/06/04 13:12:29.892,238,Post Request,204,No Content,,true,,237,1,0

但我想要像这样的东西-

2014/06/04 13:19:06.970,237,Post Request,200,OK,text,true,,782,1,0
2014/06/04 13:18:27.241,238,Post Request,200,OK,text,true,,303,1,0
2014/06/04 13:12:15.973,1124,Post Request,200,OK,text,true,,1551,1,0
2014/06/04 13:12:31.365,1429,Post Request,204,No Content,,true,,237,1,0
2014/06/04 13:12:29.892,2224,Post Request,204,No Content,,true,,237,1,0

或者相反（实际上相反对我来说更好）。

---

我做错了什么？

添加

-n

以数字排序：

$ sort -n -t"," -k2,3 file
2014/06/04 13:18:27.241,237,Post Request,200,OK,text,true,,303,1,0
2014/06/04 13:12:31.365,238,Post Request,204,No Content,,true,,237,1,0
2014/06/04 13:19:06.970,1124,Post Request,200,OK,text,true,,782,1,0
2014/06/04 13:12:29.892,1429,Post Request,204,No Content,,true,,237,1,0
2014/06/04 13:12:15.973,2224,Post Request,200,OK,text,true,,1551,1,0

或使用

-r

反转：

$ sort -rn -t"," -k2,3 file
2014/06/04 13:12:15.973,2224,Post Request,200,OK,text,true,,1551,1,0
2014/06/04 13:12:29.892,1429,Post Request,204,No Content,,true,,237,1,0
2014/06/04 13:19:06.970,1124,Post Request,200,OK,text,true,,782,1,0
2014/06/04 13:12:31.365,238,Post Request,204,No Content,,true,,237,1,0
2014/06/04 13:18:27.241,237,Post Request,200,OK,text,true,,303,1,0

从

人工分拣

：

-n，--数字排序

根据字符串数值进行比较

-r，--反向

颠倒比较的结果

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这样学习总是很有趣的