Silverlight 使用icsharpziplib压缩字节[](图像)
只有一个图像是byte[]bytes,我正在尝试压缩到Zip以便用户下载,因为我可以看到字节数组保存在MemoryStream中 问题是,当我尝试以这种方式将MemoryStream的缓冲区读取到ImagesAux时Silverlight 使用icsharpziplib压缩字节[](图像),silverlight,silverlight-5.0,savefiledialog,sharpziplib,Silverlight,Silverlight 5.0,Savefiledialog,Sharpziplib,只有一个图像是byte[]bytes,我正在尝试压缩到Zip以便用户下载,因为我可以看到字节数组保存在MemoryStream中 问题是,当我尝试以这种方式将MemoryStream的缓冲区读取到ImagesAux时zippedMemoryStream.read(ImagesAux,0,1000000)不起作用,但ImagesAux=zippedMemoryStream.ToArray()这样allready就可以工作了。。。然后stream.Write(ImagesAux,0,ImagesAu
zippedMemoryStream.read(ImagesAux,0,1000000)代码>不起作用,但ImagesAux=zippedMemoryStream.ToArray()代码>这样allready就可以工作了。。。然后stream.Write(ImagesAux,0,ImagesAux.Length)
如果要将ZipFile传递到SaveFileDialog,则无法获得ImagesAux的大小,而不是我看到的内容,ZipFile已创建,但给出了ALZip不支持的格式错误,有人能指出我做错了什么吗
MemoryStream zippedMemoryStream = new MemoryStream();
ZipOutputStream zipOutputStream;
zipOutputStream = new ZipOutputStream(zippedMemoryStream, 1000000);
zipOutputStream.SetLevel(0);
zipOutputStream.UseZip64 = UseZip64.On;
byte[] bytes = new byte[stream.Length];
stream.Read(bytes, 0, (int)stream.Length);
ZipEntry entry = new ZipEntry(ZipEntry.CleanName(ImageNameServer));//ImageNameServer
entry.DateTime = DateTime.Now;
entry.Comment = "Teste";
entry.ZipFileIndex = 1;
entry.Size = bytes.Length;
zipOutputStream.PutNextEntry(entry);
zipOutputStream.Write(bytes, 0, bytes.Length);
var something = zipOutputStream.GetType();
var lvl = zipOutputStream.GetLevel();
//zippedMemoryStream.Write(bytes, 0, bytes.Length);
zippedMemoryStream.Read(buffer, 0, bytes.Length);
MemoryStream auxxpto = new MemoryStream();
zippedMemoryStream.WriteTo(auxxpto);
buffer = auxxpto.ToArray();
private void DataSetDownload(object sender, RoutedEventArgs e)
{
var dialog = new SaveFileDialog();
dialog.Filter = "Zip Files (*.zip)|*.zip";
dialog.DefaultExt = "zip";
dialog.DefaultFileName = "DataSet.zip";
bool? fileSelected = dialog.ShowDialog();
byte[] ImagesAux = new byte[1000000];
if (fileSelected == true)
{
var value = zippedMemoryStream.CanWrite;
var read = zippedMemoryStream.CanRead;
zippedMemoryStream.Read(ImagesAux, 0, 1000000);
ImagesAux = zippedMemoryStream.ToArray();
//ZippedFile.Read(ImagesAux, 0, ImagesAux.Length);
//ImagesAux = zippedMemoryStream.ToArray();
zipOutputStream.Finish();
zipOutputStream.Close();
using (Stream stream = dialog.OpenFile())
{
stream.Write(ImagesAux, 0, ImagesAux.Length);
//stream = zippedMemoryStream.ToArray();
//stream.Flush();
//stream.Close();
}
}
}
此代码已从问题中删除。答案应该在答案中
工作代码
MemoryStream zippedMemoryStream = new MemoryStream();
ZipOutputStream zipOutputStream;
zipOutputStream = new ZipOutputStream(zippedMemoryStream, 1000000);
zipOutputStream.SetLevel(0);
zipOutputStream.UseZip64 = UseZip64.On;
byte[] bytes = new byte[stream.Length];
stream.Read(bytes, 0, (int)stream.Length);
ZipEntry entry = new ZipEntry(ZipEntry.CleanName(ImageNameServer));//ImageNameServer
zipOutputStream.PutNextEntry(entry);
zipOutputStream.Write(bytes, 0, bytes.Length);
zipOutputStream.Finish();
zipOutputStream.CloseEntry();
private void DataSetDownload(object sender, RoutedEventArgs e)
{
var dialog = new SaveFileDialog();
dialog.Filter = "Zip Files (*.zip)|*.zip";
dialog.DefaultExt = "zip";
dialog.DefaultFileName = "DataSet.zip";
bool? fileSelected = dialog.ShowDialog();
byte[] ImagesAux = new byte[1000000];
if (fileSelected == true)
{
var value = zippedMemoryStream.CanWrite;
var read = zippedMemoryStream.CanRead;
zippedMemoryStream.Position = 0;
zippedMemoryStream.Read(ImagesAux, 0, 1000000);
//ZippedFile.Read(ImagesAux, 0, ImagesAux.Length);
//ImagesAux = zippedMemoryStream.ToArray();
zipOutputStream.Finish();
zipOutputStream.Close();
using (Stream stream = dialog.OpenFile())
{
stream.Write(ImagesAux, 0, ImagesAux.Length);
//stream = zippedMemoryStream.ToArray();
//stream.Flush();
//stream.Close();
}
}
}
在读取之前,您似乎没有将zippedMemoryStream的位置更改回0。是的,您是对的,不知道它在该点处于最后一个位置,但知道它何时创建zip。文件以正确的大小显示,但仍然给出不支持的格式错误,但是感谢您的回答,至少更接近正确答案。现在解决了zipOutputStream.Finish();在错误的位置,立即编辑以显示其位置。