如何在Spring Security中获取我当前的自定义用户？

我正在使用spring安全性进行身份验证。我创建了一个从

user

扩展而来的自定义用户，然后在我的customServiceDetails（实现

UserDetailsService

）中使用它，我希望能够获得我的自定义用户，因此我尝试这样做：

public class MyUser extends User implements Serializable {


    private static final long serialVersionUID = 1L;

    private String uuid;

    public MyUser(String username, String password, boolean enabled,
            boolean accountNonExpired, boolean credentialsNonExpired,
            boolean accountNonLocked,
            Collection<? extends GrantedAuthority> authorities) {
        super(username, password, enabled, accountNonExpired,
                credentialsNonExpired, accountNonLocked, authorities);

    }

    public MyUser(String username, String password, String uuid,
            boolean enabled, boolean accountNonExpired,
            boolean credentialsNonExpired, boolean accountNonLocked,
            Collection<? extends GrantedAuthority> authorities) {
        super(username, password, enabled, accountNonExpired,
                credentialsNonExpired, accountNonLocked, authorities);
        this.uuid = uuid;
    }

    public String getUuid() {
        return uuid;
    }

    public void setUuid(String uuid) {
        this.uuid = uuid;
    }
}

我想知道有没有什么建议

试试这个

16.3.3定义@RequestMapping处理程序方法

java.security.Principal

包含当前经过身份验证的用户

@Secured({"ROLE_REGULAR_USER","ROLE_ADMIN"})
@RequestMapping(value = "/context")
public ModelAndView get(Pricipal principal) {
    String username = principal.getName();
    // Continue processing...
    return null;
}

---

我使用的是Zk框架，因此解决方案如下：

MyUser user =(MyUser)((UsernamePasswordAuthenticationToken) Executions.getCurrent().getUserPrincipal()).getPrincipal();

---

我从

UsernamePasswordAuthenticationToken

中获取当前自定义用户，当您说它不工作时…您是收到了错误（比如ClassCastException），还是只收到了null？

MyUser user =(MyUser)((UsernamePasswordAuthenticationToken) Executions.getCurrent().getUserPrincipal()).getPrincipal();