要在SQL Server的同一行上显示的Case语句

我真的很难回答一个问题

当前查询是

SELECT 
min(ID),
Date, 
CASE WHEN (ID) = '111' then SUM(Column1) END AS [Outcome1],
CASE WHEN (ID) = '222' then SUM(Column1) END AS [Outcome2],
CASE WHEN (ID) = '333' then SUM(Column1) END AS [Outcome3],
CASE WHEN (ID) = '444' then SUM(Column1) END AS [Outcome4]
FROM Table1
GROUP BY ID, Date

结果产生

|  ID |     Date | Outcome1 | Outcome2 | Outcome3 | Outcome4 |
|-----|----------|----------|----------|----------|----------|
| 111 | 01/01/18 |       20 |   (null) |   (null) |   (null) |
| 222 | 01/01/18 |   (null) |       20 |   (null) |   (null) |
| 333 | 01/01/18 |   (null) |   (null) |       20 |   (null) |
| 444 | 01/01/18 |   (null) |   (null) |   (null) |       20 |

然而，我正在寻找的结果是

|  ID |     Date | Outcome1 | Outcome2 | Outcome3 | Outcome4 |
|-----|----------|----------|----------|----------|----------|
| 111 | 01/01/18 |       20 |       20 |       20 |       20 |

我曾尝试过分组，但最终的结果是80分。但我希望它能显示4个结果栏

有人能帮我吗？谢谢

---

SQL Fiddle-

在

case

语句顶部应用

求和

聚合

SELECT 
min(ID),
Date, 
SUM(CASE WHEN (ID) = '111' then Column1 END) AS [Outcome1],
SUM(CASE WHEN (ID) = '222' then Column1 END) AS [Outcome2],
SUM(CASE WHEN (ID) = '333' then Column1 END) AS [Outcome3],
SUM(CASE WHEN (ID) = '444' then Column1 END) AS [Outcome4]
FROM Table1
GROUP BY Date

---

同时，通过在

案例

语句顶部应用

总和

聚合，从

分组中删除
ID

SELECT 
min(ID),
Date, 
SUM(CASE WHEN (ID) = '111' then Column1 END) AS [Outcome1],
SUM(CASE WHEN (ID) = '222' then Column1 END) AS [Outcome2],
SUM(CASE WHEN (ID) = '333' then Column1 END) AS [Outcome3],
SUM(CASE WHEN (ID) = '444' then Column1 END) AS [Outcome4]
FROM Table1
GROUP BY Date

同时从
分组中删除
ID
它是大小写表达式，而不是语句它是大小写表达式，而不是语句