Sql 如果前一行在特定列中具有相同的值，如何删除该行

假设我有一张桌子，看起来像这样：

-------------------------------
id|column2|column3   |column4
-------------------------------
1  value1  somevalue  somevalue
2  value2  somevalue  somevalue
3  value2  somevalue  somevalue <----- I want this column deleted
4  value3  somevalue  somevalue

-------------------------------
id |第2列|第3列|第4列
-------------------------------
1 value 1 somevalue somevalue
2 value 2 somevalue somevalue
3 value 2 somevalue somevalue
或者，如果需要按一个字段比较行

DELETE FROM Table t1
WHERE EXISTS (SELECT 1 from Table t2
              WHERE t1.Column2 = t2.Column2
              AND t2.Id > t1.Id)

我想试试这样的东西

DELETE FROM Table t1 
WHERE EXISTS (SELECT 1 from Table t2 
              WHERE t1.Column2 = t2.Column2 
              AND t2.Id + 1 = t1.Id) 

对于您的特定查询，我将使用
t2.Id+1=t1.Id
而不是
t2.Id
，因为这将删除任何事件，而不仅仅是连续条目

delete from table_name where rowid in(
select a.rowid 
from (
      select rowid,
            row_number() over (partition by column_name_having_duplicates order by                  column_name_having_duplicates)rnk 
from table_name a
)a
where a.rnk>1);

delete from table_name where rowid in(
select a.rowid 
from (
      select rowid,
            row_number() over (partition by column_name_having_duplicates order by                  column_name_having_duplicates)rnk 
from table_name a
)a
where a.rnk>1);