来自同一列但不同条件的SQL计数获取所有列的稍后计数结果

我试图对不同条件下的同一列进行计数，但对其他条件也会得到稍后的计数结果

对于此sql：

select count(eqa.ID) as gold_yes  from EC_SECTION_ANSWER esa , EC_QUESTION_ANSWER eqa 
where esa.SC_NUMBER = 1079 and esa.ID = eqa.SC_ID and eqa.QU_ANSWER = 'Yes' and   eqa.QU_TYPE = 'abc';

我正在获得输出

gold\u是：

1

同样，如果我在不同的条件下运行sql：

select count(eqa.ID) as gold_no  from EC_SECTION_ANSWER esa , EC_QUESTION_ANSWER eqa 
where esa.SC_NUMBER = 1079 and esa.ID = eqa.SC_ID and eqa.QU_ANSWER = 'No' and  eqa.QU_TYPE = 'abc';

我正在获取输出

gold\u编号：

0

现在，如果运行sql组合：

select count(eqa.ID) as gold_yes ,count(eqa_2.ID) as gold_no  from EC_SECTION_ANSWER esa , EC_QUESTION_ANSWER eqa ,EC_SECTION_ANSWER esa_2 , EC_QUESTION_ANSWER eqa_2 
where esa.SC_NUMBER = 1079 and esa.ID = eqa.SC_ID and eqa.QU_ANSWER = 'Yes' and   eqa.QU_TYPE = 'abc'
and esa_2.SC_NUMBER = 1079 and esa_2.ID = eqa_2.SC_ID and eqa_2.QU_ANSWER = 'No' and eqa_2.QU_TYPE = 'abc'; 

我正在获取输出：

gold\u是：

0

和

gold\u否：

0

。哪个应该是

gold\u是：

1

和

gold\u否：

0

谁能告诉我我犯了什么错误吗

---

提前谢谢

将

where

子句中的条件放入

案例中

，并对其进行汇总

select sum(case when esa.SC_NUMBER = 1079 
                     and eqa.QU_ANSWER = 'Yes' 
                     and eqa.QU_TYPE = 'abc'
                then 1
                else 0
           end) as gold_yes
...
from EC_SECTION_ANSWER esa
join EC_QUESTION_ANSWER eqa on esa.ID = eqa.SC_ID

---

查询中的

WHERE

条件是问题所在：您不能同时拥有

eqa.QU\u ANSWER='Yes'

和

eqa.QU\u ANSWER='No'

，因此查询返回0行，并且0行的值计数也为0

您可以将条件更改为

或

，也可以在

计数

中采用相同的条件，同时还应将查询更改为使用显式的

联接

，而不是在

WHERE

子句中写入联接条件

SELECT COUNT(CASE WHEN eqa.QU_ANSWER = 'Yes' THEN 1 ELSE NULL END) as gold_yes
     , COUNT(CASE WHEN eqa.QU_ANSWER = 'No' THEN 1 ELSE NULL END) as gold_no
FROM   EC_SECTION_ANSWER esa
       INNER JOIN EC_QUESTION_ANSWER eqa ON esa.ID = eqa.SC_ID
WHERE  esa.SC_NUMBER = 1079 
  AND  eqa.QU_TYPE = 'abc'; 

试试这个：

SELECT SUM(CASE WHEN (esa.SC_NUMBER = 1079 and 
                      esa.ID = eqa.SC_ID   and 
                      eqa.QU_ANSWER = 'Yes'and  
                      eqa.QU_TYPE = 'abc') 
           THEN 1 END) AS eqacount1
       SUM(CASE WHEN (esa.SC_NUMBER = 1079 and 
                      esa.ID = eqa.SC_ID   and
                      eqa.QU_ANSWER = 'No' and 
                      eqa.QU_TYPE = 'abc') 
          THEN 1 END)  AS eqacount2 
from EC_SECTION_ANSWER esa , EC_QUESTION_ANSWER eqa

: 它会工作的，检查一下

问候,，

---

Praveen Nelge

您已将连接条件移动到聚合函数中。这对性能来说真是个坏主意。

SELECT SUM(CASE WHEN (esa.SC_NUMBER = 1079 and 
                      esa.ID = eqa.SC_ID   and 
                      eqa.QU_ANSWER = 'Yes'and  
                      eqa.QU_TYPE = 'abc') 
           THEN 1 END) AS eqacount1
       SUM(CASE WHEN (esa.SC_NUMBER = 1079 and 
                      esa.ID = eqa.SC_ID   and
                      eqa.QU_ANSWER = 'No' and 
                      eqa.QU_TYPE = 'abc') 
          THEN 1 END)  AS eqacount2 
from EC_SECTION_ANSWER esa , EC_QUESTION_ANSWER eqa