SQL如何计算每个日期的所有剩余值

我有以下SQL函数

CREATE FUNCTION [dbo].[GetCardDepartRemains] 
(
    @CardId INT,
    @DepartId INT,
    @Date DATETIME = NULL,
    @DocumentId INT = NULL
)
RETURNS INT
AS
BEGIN
    DECLARE @Res INT

    SELECT
        @Res = ISNULL(SUM(CASE WHEN Operations.[Output] = 0 AND Operations.RecipientId = @DepartId THEN 1 ELSE -1 END), 0)
    FROM dbo.Operations
    WHERE  Operations.CardId = @CardId
        AND (Operations.[Output] = 0 AND Operations.RecipientId = @DepartId OR Operations.Input = 0 AND Operations.SenderId = @DepartId)
        AND (@Date IS NULL OR Operations.[Date] <= @Date)

    RETURN @Res
END
GO

但是这个查询的执行时间超过了2分钟，所以我们需要编写一个新的查询

我的查询可以在特定日期（例如“2016-10-04”）找到每个部门每张卡的所有剩余部分

SELECT 
    [Card],
    Depart,
    Res
FROM          
    (SELECT
        Cards.Id as [Card],
        Departments.Id as Depart,
        ISNULL(SUM(CASE WHEN Operations.[Output] = 0 AND Operations.RecipientId = Departments.Id THEN 1 ELSE -1 END), 0) as Res
    FROM Operations
    CROSS JOIN Cards
    CROSS JOIN Departments
    WHERE  Operations.CardId = Cards.Id
    AND (Operations.[Output] = 0 AND Operations.RecipientId = Departments.Id OR Operations.Input = 0 AND Operations.SenderId = Departments.Id)
    AND (Operations.[Date] <= '2016-10-04') 

    GROUP BY Cards.Id, Departments.Id
    ) as X
WHERE Res = -1

---

是否可以帮助重新编写此查询以查找所有日期的剩余内容？

假设SQL Server为2008或更高版本：

要查找所有日期，只需按如下方式注释掉日期筛选器：

-- AND (Operations.[Date] <= '2016-10-04') 

---

将-30更改为过去的天数。所以一年前应该是-364。

您使用的是哪个版本的sql server？只需将函数更改为内联函数就足够了。使用标量函数的问题在于，它会对查询中的每一行执行两次，而SQL server在逐行迭代中表现不佳。

-- AND (Operations.[Date] <= '2016-10-04') 

AND (Operations.[Date] between between getDate()-30 and getDate()