Sql 在access中显示重复行
我有这张桌子Sql 在access中显示重复行,sql,ms-access,Sql,Ms Access,我有这张桌子 男人 id | Qty | Place ======================== 111 | 10 | 55 111 | 20 | 66 111 | 10 | 77 222 | 40 | 11 333 | 50 | 11 111 | 10 | 22 222 | 44 | 33 222 | 40 | 44 333 | 15
男人
id | Qty | Place
========================
111 | 10 | 55
111 | 20 | 66
111 | 10 | 77
222 | 40 | 11
333 | 50 | 11
111 | 10 | 22
222 | 44 | 33
222 | 40 | 44
333 | 15 | 55
我需要显示id=id和Qty=Qty的所有记录,如下所示:
id | Qty | Place
=====================
111 | 10 | 55
111 | 10 | 77
111 | 10 | 22
222 | 40 | 11
222 | 40 | 44
SELECT MEN.Id, MEN.Qty, MEN.Place
FROM MEN INNER JOIN
(SELECT MEN.Id, MEN.Qty
FROM MEN
GROUP BY MEN.Id, MEN.Qty
HAVING (((Count(*))>1))) AS a
ON (MEN.Qty = a.Qty) AND (MEN.Id = a.Id)
ORDER BY MEN.Id, MEN.Qty;
试试这个
SELECT T.ID,T.Qty
FROM Table1 T
GROUP BY T.ID,T.Qty
HAVING (((Count(*))>1));
使用以下查询获取完整的记录详细信息集:
SELECT R.Id, R.Qty, R.Place
FROM Table1 R INNER JOIN
(
SELECT T.Id, T.Qty
FROM Table1 T
GROUP BY T.Id, T.Qty
HAVING (((Count(*))>1))
)AS JR ON R.Qty = JR.Qty AND R.Id = JR.Id
试试这个
SELECT T.ID,T.Qty
FROM Table1 T
GROUP BY T.ID,T.Qty
HAVING (((Count(*))>1));
使用以下查询获取完整的记录详细信息集:
SELECT R.Id, R.Qty, R.Place
FROM Table1 R INNER JOIN
(
SELECT T.Id, T.Qty
FROM Table1 T
GROUP BY T.Id, T.Qty
HAVING (((Count(*))>1))
)AS JR ON R.Qty = JR.Qty AND R.Id = JR.Id
您可以这样做:
id | Qty | Place
=====================
111 | 10 | 55
111 | 10 | 77
111 | 10 | 22
222 | 40 | 11
222 | 40 | 44
SELECT MEN.Id, MEN.Qty, MEN.Place
FROM MEN INNER JOIN
(SELECT MEN.Id, MEN.Qty
FROM MEN
GROUP BY MEN.Id, MEN.Qty
HAVING (((Count(*))>1))) AS a
ON (MEN.Qty = a.Qty) AND (MEN.Id = a.Id)
ORDER BY MEN.Id, MEN.Qty;
创建内部查询以查找存在多个Id实例的位置,然后将其连接回原始表以获取位置值。您可以执行以下操作:
id | Qty | Place
=====================
111 | 10 | 55
111 | 10 | 77
111 | 10 | 22
222 | 40 | 11
222 | 40 | 44
SELECT MEN.Id, MEN.Qty, MEN.Place
FROM MEN INNER JOIN
(SELECT MEN.Id, MEN.Qty
FROM MEN
GROUP BY MEN.Id, MEN.Qty
HAVING (((Count(*))>1))) AS a
ON (MEN.Qty = a.Qty) AND (MEN.Id = a.Id)
ORDER BY MEN.Id, MEN.Qty;
创建内部查询以查找存在多个Id实例的位置,然后将其连接回原始表以获取位置值