Sql Postgres中基于多行比较操作的表列更新
我在博士后有下表Sql Postgres中基于多行比较操作的表列更新,sql,postgresql,group-by,max,Sql,Postgresql,Group By,Max,我在博士后有下表 id num EBI-1002144 1 EBI-1002144 1 EBI-1002142 2 EBI-1002142 2 EBI-1002635 1 EBI-1002635 1 EBI-1002635 2 EBI-1002635 2 EBI-1003351 1 EBI-1003351 1 EBI-1003351 2 EBI-1003351 2 EBI-1003469 1 EBI-1003469 1 EBI-1003469 2 EBI-1003469 2 E
id num
EBI-1002144 1
EBI-1002144 1
EBI-1002142 2
EBI-1002142 2
EBI-1002635 1
EBI-1002635 1
EBI-1002635 2
EBI-1002635 2
EBI-1003351 1
EBI-1003351 1
EBI-1003351 2
EBI-1003351 2
EBI-1003469 1
EBI-1003469 1
EBI-1003469 2
EBI-1003469 2
EBI-1003574 1
EBI-1003574 1
EBI-1003574 2
EBI-1003574 2
我想根据以下条件在此表中追加另一列:
--> group by id
--> calculate max of num
--> if the value of num > 1 per id, then assign the id as label 'A' else 'B'
我能够找出最大值,但无法找出如何将该值分配给具有公共id的每一行
预期产出为:
id num label
EBI-1002144 1 B
EBI-1002144 1 B
EBI-1002142 1 A
EBI-1002142 2 A
EBI-1002635 1 A
EBI-1002635 1 A
EBI-1002635 2 A
EBI-1002635 2 A
EBI-1003351 1 A
EBI-1003351 1 A
EBI-1003351 2 A
EBI-1003351 2 A
EBI-1003469 1 A
EBI-1003469 1 A
EBI-1003469 2 A
EBI-1003469 2 A
EBI-1003574 1 A
EBI-1003574 1 A
EBI-1003574 2 A
EBI-1003574 2 A
您可以使用窗口函数 如果需要update语句:
with cte as (
select
id,
case
when max(num) over(partition by id) > 1
then 'A'
else 'B'
end label
from mytable t
)
update mytable
set label = cte.label
from cte
where cte.id = mytable.id
如果您需要选择:
使用窗口功能:
select t.*,
(case when max(num) over (partition by id) > 1 then 'A' else 'B' end) as label
from t;
如果确实要更新表,请聚合并联接:
select t.*,
(case when max(num) over (partition by id) > 1 then 'A' else 'B' end) as label
from t;
update t
set label = (case when max_num > 1 then 'A' else 'B' end)
from (select id, max(num) as max_num
from t
group by id
) tt
where tt.id = t.id