Warning: file_get_contents(/data/phpspider/zhask/data//catemap/7/sql-server/27.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181

Warning: file_get_contents(/data/phpspider/zhask/data//catemap/0/backbone.js/2.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Sql 将分隔为新列的管道拆分_Sql_Sql Server_Sql Server 2008_Tsql - Fatal编程技术网

Sql 将分隔为新列的管道拆分

Sql 将分隔为新列的管道拆分,sql,sql-server,sql-server-2008,tsql,Sql,Sql Server,Sql Server 2008,Tsql,我必须将一列管道分隔成新的列 例:第1栏:数据| 7-8 | 5 它应该分成两部分 col2 col3 col4 Data 7-8 5 请帮我解决这个问题。玩一玩。这有点冗长,但说明了操作的每个步骤。我鼓励您提出任何后续问题 DECLARE @t table ( piped varchar(50) ) INSERT INTO @t (piped) VALUES ('pipe|delimited|values')

我必须将一列管道分隔成新的列

例:第1栏:数据| 7-8 | 5

它应该分成两部分

col2          col3         col4
Data          7-8          5

请帮我解决这个问题。

玩一玩。这有点冗长,但说明了操作的每个步骤。我鼓励您提出任何后续问题

DECLARE @t table (
   piped varchar(50)
)

INSERT INTO @t (piped)
  VALUES ('pipe|delimited|values')
       , ('a|b|c');

; WITH x AS (
  SELECT piped
       , CharIndex('|', piped) As first_pipe
  FROM   @t
)
, y AS (
  SELECT piped
       , first_pipe
       , CharIndex('|', piped, first_pipe + 1) As second_pipe
       , SubString(piped, 0, first_pipe) As first_element
  FROM   x
)
, z AS (
  SELECT piped
       , first_pipe
       , second_pipe
       , first_element
       , SubString(piped, first_pipe  + 1, second_pipe - first_pipe - 1) As second_element
       , SubString(piped, second_pipe + 1, Len(piped) - second_pipe) As third_element
  FROM   y
)
SELECT *
FROM   z

可能有数百种比这更好的方法,但是

declare @string as varchar(100)
set @string = 'Data|7-8|5'
select left(@string,CHARINDEX('|',@string,0) -1) as one, 
left(substring(@string,CHARINDEX('|',@string,0)+1,100),CHARINDEX('|',substring(@string,CHARINDEX('|',@string,0)+1,100),0) -1) as two,
reverse(left(reverse(@string),CHARINDEX('|',reverse(@string),0) -1)) as three
测试数据:-

create table #test (
    col1 varchar(50)
)
go
insert into #test values
    ('Data|7-8|5'),
    ('Data|asdsad|sad'),
    ('fish|c cx cx xc cc xc cx |ededededeed'),
    ('Data|iueroiheqroqer|ewoijewijewd5'),
    ('tune||5'),
    ('Data||')
go
对于格式错误的输入,函数需要更多的防御性编程:-

create function dbo.GetDomain(
    @source varchar(1024),
    @delimiter varchar(10),
    @domain int
) returns varchar(1024) as begin
    declare @returnValue varchar(1024)
    declare @workingOn int
    declare @length int
    set @workingOn=0
    while @workingOn<@domain begin
        set @source=substring(@source,charindex(@delimiter,@source)+1,1024)
        set @workingOn+=1
    end
    set @length=charindex(@delimiter,@source)
    set @returnValue=substring(@source,1,case when @length=0 then 1024 else @length-1 end)
    return @returnValue
end
go
产生:-

col1                                     col2  col3                 col4
Data|7-8|5                               Data  7-8                  5
Data|asdsad|sad                          Data  asdsad               sad
fish|c cx cx xc cc xc cx |ededededeed    fish  c cx cx xc cc xc cx  ededededeed
Data|iueroiheqroqer|ewoijewijewd5        Data  iueroiheqroqer       ewoijewijewd5
tune||5                                  tune                       5
Data||                                   Data

我最喜欢的解决这类问题的方法之一是使用XML数据类型。我对它的性能不太了解,但它确实起到了作用

DECLARE @line VARCHAR(MAX);
DECLARE @x xml;

/* example data */
SET @line = 'Data|7-8|5';


/* replace the delimeter with closing and opening tags,
   and wrap the line with opening and closing tags as well */
SET @x = Cast(
        '<field>'
        + replace(@line, '|', '</field><field>')
        + '</field>' AS XML);


/* query the nodes based on index */
SELECT
    @x.query('field[1]').value('.','VarChar(10)')   Col1
    ,@x.query('field[2]').value('.','VarChar(10)')  Col2
    ,@x.query('field[3]').value('.','Int')          Col3

总是有固定数量的管道吗?是的,只有两条管道。。必须分成三列询问代码必须表明对所解决问题的最低理解。包括尝试的解决方案,以及它们不起作用的原因。选择col1,LEFTcol1,isnullifcharindex'|',col1-1,-1,LENcol1作为col2,LEFTcol2,ISNULLNULLIFCHARINDEX'|',col1-1,-1,LENcol1-1作为col3,RIGHTcol1,LENcol isnullifcharindex'|',col1-1,-2,LENcol1作为col4从mytableI上面的查询中尝试过。我无法正确获取col2,但无法将第二个管道拆分为col3和col4。
DECLARE @line VARCHAR(MAX);
DECLARE @x xml;

/* example data */
SET @line = 'Data|7-8|5';


/* replace the delimeter with closing and opening tags,
   and wrap the line with opening and closing tags as well */
SET @x = Cast(
        '<field>'
        + replace(@line, '|', '</field><field>')
        + '</field>' AS XML);


/* query the nodes based on index */
SELECT
    @x.query('field[1]').value('.','VarChar(10)')   Col1
    ,@x.query('field[2]').value('.','VarChar(10)')  Col2
    ,@x.query('field[3]').value('.','Int')          Col3