从2个SQL查询进行计算

我有两个查询，我不知道如何运行作为一个做一些简单的数学

SELECT count(*) FROM CUSTOMERINFO
where member between '2013-01-01' and '2013-12-31' 

退货：7823

select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo 
where code = '810samp' 
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between '2013-01-01' and '2013-12-31' 

报税表：4106

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我需要查询返回：4106/7823 X 100

未测试代码，但这应该可以为您完成：

SELECT (SELECT count(*) FROM CUSTOMERINFO
where member between '2013-01-01' and '2013-12-31') / 
(select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo 
where code = '810samp' 
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between '2013-01-01' and '2013-12-31')
* 100 

另一个是

DECLARE @int1 as int
DECLARE @int2 as int
SET @int1 = (SELECT count(*) FROM CUSTOMERINFO
    where member between '2013-01-01' and '2013-12-31')
SET @int2 = (select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo 
    where code = '810samp' 
    AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
    AND orderinfo.PrepareDate between '2013-01-01' and '2013-12-31')
SELECT @int1/@int2 X 100

只需使用以下语法：

SELECT (
  CAST((<your first query>) as decimal)
  /(<your second query>)
  * 100
  ) AS Percents;

---

看看是MySQL还是MS SQL Server？

SELECT (
  CAST((select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo 
        where code = '810samp' 
        AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
        AND orderinfo.PrepareDate between '2013-01-01' and '2013-12-31') as decimal)
  /(SELECT count(*) FROM CUSTOMERINFO
    where member between '2013-01-01' and '2013-12-31')
  * 100
  ) AS Percents;