将不同的行分组到sql server的单行中

结果集查询的链接

我想在单行中显示没有空值的数据

with cte as (
    Select QuestionID,SubmitDate,
    Case when  QuestionID=860 and Answers='Yes' then   Answers    End as 'Ans1A',
    case when  QuestionID=861 then Answers else NULL End as 'Answer2A',
    case when  QuestionID=862 then Answers  ELSE NULL End as 'Answer3A',
    case when  QuestionID=863 then Answers  Else NULL End as 'Answer4A',
    Case when  QuestionID=864 and Answers='Yes' then   Answers    End as 'Ans2B',
    case when  QuestionID=865 then Answers else NULL End as 'Answer2B',
    case when  QuestionID=866 then Answers  ELSE NULL End as 'Answer3B',
    case when  QuestionID=867 then Answers  Else NULL End as 'Answer4B'
     From Question_Users Where SurveyId=28 and QuestionID in (860,861,862,863,864,865,866,867) and SubmitDate is not null
     )
select * 
from cte

上述sql查询的示例数据

QID + Ans1A + Ans2A+ Ans3A,Ans4A+ Ans1B+Ans2B+Ans3B+Ans4B   
860   + Yes +  Null + Null +   Null +   Null  + Null + Null +  Null
861   + Null + abc + Null +   Null +   Null  + Null + Null +  Null
862   + Null + Null + abc +   Null +   Null  + Null + Null +  Null
863   + Null + Null + Null +   abc+   Null  + Null + Null + Null
864   + Null + Null + Null +   Null  +   abc+ Null + Null + Null
864   + Null + Null + Null +   Null  +   Null  + abc+ Null + Null
864   + Null + Null + Null +   Null  +   Null  + Null + abc+ Null
864   + Null + Null + Null +   Null  +   Null  + Null + Null + abc
860   + Yes +  Null + Null +   Null +   Null  + Null + Null +  Null
861   + Null + abc + Null +   Null +   Null  + Null + Null +  Null
862   + Null + Null + abc +   Null +   Null  + Null + Null +  Null
863   + Null + Null + Null +   abc+   Null  + Null + Null + Null
864   + Null + Null + Null +   Null  +   abc+ Null + Null + Null
864   + Null + Null + Null +   Null  +   Null  + abc+ Null + Null
864   + Null + Null + Null +   Null  +   Null  + Null + abc+ Null
864   + Null + Null + Null +   Null  +   Null  + Null + Null + abc

---

我认为您可以使用聚合：

Select submitdate,
       max(Case when  QuestionID=860 and Answers='Yes' then Answers End) as Ans1A,
       max(case when  QuestionID=861 then Answers End) as Answer2A,
       max(case when  QuestionID=862 then Answers End) as Answer3A,
       max(case when  QuestionID=863 then Answers End) as Answer4A,
       max(Case when  QuestionID=864 and Answers='Yes' then Answers end) as Ans2B,
       max(case when  QuestionID=865 then Answers end) as Answer2B,
       max(case when  QuestionID=866 then Answers end) as Answer3B,
       max(case when  QuestionID=867 then Answers end) as Answer4B
From Question_Users
Where SurveyId = 28 and
      QuestionID in (860, 861, 862, 863, 864, 865, 866, 867) and
      SubmitDate is not null
Group by submitdate;

---

请编辑您的问题并提供示例数据和所需结果。您尝试过的任何查询都很有用。我也使用了pivot表，但它只返回一行，我尝试在上面的查询中返回一行。您的示例数据表明您只需要一行。也许您希望通过

.submitdate

进行聚合。