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Sql 不久前得到了另一个有效的答案-关于3号订单的好信息。不知道:-)所以我猜“选择顶部…”和“订购人…描述”总是粘在一起的?((还有)我喜欢不需要额外的括号(在你的解决方案中)) WITH Calendar AS (SELECT CAST(@Start_Sql_Visual Studio 2008_Sql Server 2005 - Fatal编程技术网

Sql 不久前得到了另一个有效的答案-关于3号订单的好信息。不知道:-)所以我猜“选择顶部…”和“订购人…描述”总是粘在一起的?((还有)我喜欢不需要额外的括号(在你的解决方案中)) WITH Calendar AS (SELECT CAST(@Start

Sql 不久前得到了另一个有效的答案-关于3号订单的好信息。不知道:-)所以我猜“选择顶部…”和“订购人…描述”总是粘在一起的?((还有)我喜欢不需要额外的括号(在你的解决方案中)) WITH Calendar AS (SELECT CAST(@Start,sql,visual-studio-2008,sql-server-2005,Sql,Visual Studio 2008,Sql Server 2005,不久前得到了另一个有效的答案-关于3号订单的好信息。不知道:-)所以我猜“选择顶部…”和“订购人…描述”总是粘在一起的?((还有)我喜欢不需要额外的括号(在你的解决方案中)) WITH Calendar AS (SELECT CAST(@StartDate AS datetime) AS Date UNION ALL SE

不久前得到了另一个有效的答案-关于3号订单的好信息。不知道:-)所以我猜“选择顶部…”和“订购人…描述”总是粘在一起的?((还有)我喜欢不需要额外的括号(在你的解决方案中))
WITH Calendar AS (SELECT     CAST(@StartDate AS datetime) AS Date
                                          UNION ALL
                                          SELECT     DATEADD(d, 1, Date) AS Expr1
                                          FROM         Calendar AS Calendar_1
                                          WHERE     (DATEADD(d, 1, Date) < @EndDate))
    SELECT     C.Date, C2.Country, COALESCE (SUM(R.[Amount of people per day needed]), 0) AS [Allocated testers]
     FROM         Calendar AS C CROSS JOIN
                            Country AS C2 LEFT OUTER JOIN
                            Requests AS R ON C.Date BETWEEN R.[Start date] AND R.[End date] AND R.CountryID = C2.CountryID
     WHERE     (C2.Country = @Country)
     GROUP BY C.Date, C2.Country OPTION (MAXRECURSION 0)
Date            Country         Allocated testers
06/01/2010      Chile             3
06/02/2010      Chile             4
06/03/2010      Chile             0
06/04/2010      Chile             0
06/05/2010      Chile            19
Allocated testers
           19
ORDER BY 'people needed DESC' LIMIT 1 
select TOP 1 .... ORDER BY 'people needed' DESC
WITH  Calendar
        AS (
             SELECT
              CAST(@StartDate AS datetime) AS Date
             UNION ALL
             SELECT
              DATEADD(d, 1, Date) AS Expr1
             FROM
              Calendar AS Calendar_1
             WHERE
              ( DATEADD(d, 1, Date) < @EndDate )
           )
SELECT TOP 1 *
FROM 
(           
  SELECT
    C.Date
   ,C2.Country
   ,COALESCE(SUM(R.[Amount of people per day needed]), 0) AS [Allocated testers]
  FROM
    Calendar AS C
    CROSS JOIN Country AS C2
    LEFT OUTER JOIN Requests AS R
      ON C.Date BETWEEN R.[Start date] AND R.[End date]
         AND R.CountryID = C2.CountryID
  WHERE
    ( C2.Country = @Country )
  GROUP BY
    C.Date
   ,C2.Country
OPTION
    ( MAXRECURSION 0 )
    ) lst
    ORDER BY lst.[Allocated testers] DESC
WITH Calendar AS (SELECT     CAST(@StartDate AS datetime) AS Date
                  UNION ALL
                  SELECT     DATEADD(d, 1, Date) AS Expr1
                  FROM         Calendar AS Calendar_1
                   WHERE     (DATEADD(d, 1, Date) < @EndDate))
SELECT  TOP 1   C.Date, C2.Country, COALESCE (SUM(R.[Amount of people per day needed]), 0) AS [Allocated testers]
FROM    Calendar AS C CROSS JOIN
        Country AS C2 LEFT OUTER JOIN
        Requests AS R ON C.Date BETWEEN R.[Start date] AND R.[End date] AND R.CountryID = C2.CountryID
WHERE     (C2.Country = @Country)
GROUP BY C.Date, C2.Country 
ORDER BY 3 DESC
OPTION (MAXRECURSION 0)