Sql 如何查看行之间的更改?
我有一张看起来像的桌子Sql 如何查看行之间的更改?,sql,hiveql,Sql,Hiveql,我有一张看起来像的桌子 object_id attribute_1 attribute_2 attribute_3 1 a a a 1 a a a 1 a b a 1 a a a 2
object_id attribute_1 attribute_2 attribute_3
1 a a a
1 a a a
1 a b a
1 a a a
2 z z z
2 w z z
我想了解用户对这些对象所做的更改。一个潜在的最终结果可能是一个对象表,其中的属性被更改的次数,以及对象被记录的总次数,如下所示:
object_id attribute_1 attribute_2 attribute_3 count
1 0 2 0 3
2 1 0 0 2
我将如何做到这一点?量化和理解所做更改的其他潜在方法有哪些?如果在将属性更改回以前的值时不需要将更改计算在内,则可以按对象id和属性分组,以获得该属性的不同值的数量 我建议您编写一个应用程序或一个过程来计算您想要的内容。但是,如果您只想通过一个查询来解决问题,那么应该是这样的:
SELECT object_id,
sum(changes_attribute_1) AS changes_attribute_1,
sum(changes_attribute_2) AS changes_attribute_2
FROM
( SELECT object_id,
sum(IF(atribute = 2,changes,0)) AS changes_attribute_2,
sum(IF(atribute = 1,changes,0)) AS changes_attribute_1
FROM
(SELECT count(*)-1 AS changes,
object_id,
1 AS atribute
FROM
(SELECT count(*),
object_id
FROM TABLE AS inner_table
GROUP BY object_id,
attribute_1) AS tudo
GROUP BY object_id
UNION ALL SELECT count(*)-1 AS changes,
object_id,
2 AS atribute
FROM
(SELECT count(*),
object_id
FROM TABLE AS inner_table
GROUP BY object_id,
attribute_2) AS tudo
GROUP BY object_id) AS tudo
GROUP BY object_id,
atribute) AS tudo2
GROUP BY object_id
我已尝试使用此表进行查询:
object_id, attribute_1, attribute_2
1, 1, 1
1, 2, 1
1, 3, 2
2, 1, 1
2, 2, 2
2, 3, 4
我得到了这个结果
# object_id, changes_attribute_1, changes_attribute_2
1, 2, 1
2, 2, 2