Sql 有自定义的年份,而不是日历年
我希望这一年从八月开始,在接下来的七月结束。除了写我每年都要写的丑陋的Sql 有自定义的年份,而不是日历年,sql,postgresql,Sql,Postgresql,我希望这一年从八月开始,在接下来的七月结束。除了写我每年都要写的丑陋的IFELSE语句之外,还有什么简单的方法可以做到这一点吗?理想情况下,我希望有像2009-10、2010-11等这样的一年。我使用的是Postgres 下面是一个示例查询,我想通过它来获取自定义年份 Select extract(year from created) as Year, type, count(*) from table group by Year, type order by Year 如果有任何帮助,我们
IFELSE
语句之外,还有什么简单的方法可以做到这一点吗?理想情况下,我希望有像2009-10、2010-11等这样的一年。我使用的是Postgres
下面是一个示例查询,我想通过它来获取自定义年份
Select extract(year from created) as Year, type, count(*)
from table
group by Year, type
order by Year
如果有任何帮助,我们将不胜感激,TIA。考虑建立一个日期表。使用此日期表,您可以将各种数据与每个日期关联,例如会计年度、季度、月份、假日、周末等。考虑设置日期表。使用此日期表,您可以将各种数据与每个日期关联,例如会计年度、季度、月份、假日、周末等
SELECT (CASE WHEN (EXTRACT(month FROM created) > 6) THEN CAST(EXTRACT(year FROM created) AS text) || '-' || CAST(EXTRACT(year FROM created) +1 AS text) ELSE (CAST(EXTRACT(year FROM created) - 1 AS text) || '-' || CAST(EXTRACT(year FROM created) AS text)) END) AS CustomYear
FROM asmt.testscores order by created desc LIMIT 10000
这似乎成功了
select
extract(year from created + interval '6 months') as "Year",
type,
count(*)
from table
group by 1, 2
order by 1
这似乎成功了
select
extract(year from created + interval '6 months') as "Year",
type,
count(*)
from table
group by 1, 2
order by 1