Oracle SQL-不在子查询中

我对这个和使用Oracle SQL还不熟悉。我有以下表格：

表1案例详情

CaseNumber | CaseType
1          | 'RelevantToThisQuestion'
2          | 'RelevantToThisQuestion'
3          | 'RelevantToThisQuestion'
4          | 'NotRelevantToThisQuestion'

表2LinkedPeople

CaseNumber | RelationshipType | LinkedPerson
1          | 'Owner'          | 123
1          | 'Agent'          | 124
1          | 'Contact'        | 125
2          | 'Owner'          | 126
2          | 'Agent'          | 127
2          | 'Contact'        | 128
3          | 'Owner'          | 129
3          | 'Agent'          | 130
3          | 'Contact'        | 131

表3位置

LinkedPerson| Country
123         | 'AU'
124         | 'UK'
125         | 'UK'
126         | 'US'
127         | 'US'
128         | 'UK'
129         | 'UK'
130         | 'AU'
131         | 'UK'

我想统计与这个问题相关的案例数量，在“AU”中没有相关人员。因此，上述数据的结果为1

我一直在尝试将聚合函数和子查询结合起来，但我认为这可能过于复杂了

---

只需要往正确的方向推一下，谢谢

我不确定确切的语法，但我相信您想要的是：

---

选择count distinct case number from LinkedPeople where Country！='要获取所有记录，请执行以下操作：

SELECT COUNT(DISTINCT CaseNumber) 
FROM LinkedPeople
WHERE CaseNumber NOT IN 
(
  SELECT DISTINCT C.CaseNumber
  FROM CaseDetail C       
  INNER JOIN LinkedPeople P ON C.CaseNumber = P.CaseNumber
  INNER JOIN Location L
  ON P.LinkedPerson = L.LinkedPerson
  WHERE Country = 'AU' AND C.CaseType = 'RelevantToThisQuestion'
)


Oracle 11g R2架构设置：

CREATE TABLE CASEDETAIL ( CaseNumber, CaseType ) AS
          SELECT 1, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 2, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 3, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 4, 'NotRelevantToThisQuestion' FROM DUAL;

CREATE TABLE LINKEDPEOPLE ( CaseNumber, RelationshipType, LinkedPerson ) AS
          SELECT 1, 'Owner', 123 FROM DUAL
UNION ALL SELECT 1, 'Agent', 124 FROM DUAL
UNION ALL SELECT 1, 'Contact', 125 FROM DUAL
UNION ALL SELECT 2, 'Owner', 126 FROM DUAL
UNION ALL SELECT 2, 'Agent', 127 FROM DUAL
UNION ALL SELECT 2, 'Contact', 128 FROM DUAL
UNION ALL SELECT 3, 'Owner', 129 FROM DUAL
UNION ALL SELECT 3, 'Agent', 130 FROM DUAL
UNION ALL SELECT 3, 'Contact', 131 FROM DUAL;

CREATE TABLE LOCATION ( LinkedPerson, Country ) AS
          SELECT 123, 'AU' FROM DUAL
UNION ALL SELECT 124, 'UK' FROM DUAL
UNION ALL SELECT 125, 'UK' FROM DUAL
UNION ALL SELECT 126, 'US' FROM DUAL
UNION ALL SELECT 127, 'US' FROM DUAL
UNION ALL SELECT 128, 'UK' FROM DUAL
UNION ALL SELECT 129, 'UK' FROM DUAL
UNION ALL SELECT 130, 'AU' FROM DUAL
UNION ALL SELECT 131, 'UK' FROM DUAL;

SELECT COUNT( DISTINCT CASENUMBER ) AS Num_Relevant_Cases
FROM   CASEDETAIL c
WHERE  CaseType = 'RelevantToThisQuestion'
AND    NOT EXISTS ( SELECT 1
                    FROM   LINKEDPEOPLE p
                           INNER JOIN LOCATION l
                           ON ( p.LinkedPerson = l.LinkedPerson )
                    WHERE  c.CaseNumber = p.CaseNumber
                    AND    l.Country = 'AU' )

| NUM_RELEVANT_CASES |
|--------------------|
|                  1 |

查询1：

CREATE TABLE CASEDETAIL ( CaseNumber, CaseType ) AS
          SELECT 1, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 2, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 3, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 4, 'NotRelevantToThisQuestion' FROM DUAL;

CREATE TABLE LINKEDPEOPLE ( CaseNumber, RelationshipType, LinkedPerson ) AS
          SELECT 1, 'Owner', 123 FROM DUAL
UNION ALL SELECT 1, 'Agent', 124 FROM DUAL
UNION ALL SELECT 1, 'Contact', 125 FROM DUAL
UNION ALL SELECT 2, 'Owner', 126 FROM DUAL
UNION ALL SELECT 2, 'Agent', 127 FROM DUAL
UNION ALL SELECT 2, 'Contact', 128 FROM DUAL
UNION ALL SELECT 3, 'Owner', 129 FROM DUAL
UNION ALL SELECT 3, 'Agent', 130 FROM DUAL
UNION ALL SELECT 3, 'Contact', 131 FROM DUAL;

CREATE TABLE LOCATION ( LinkedPerson, Country ) AS
          SELECT 123, 'AU' FROM DUAL
UNION ALL SELECT 124, 'UK' FROM DUAL
UNION ALL SELECT 125, 'UK' FROM DUAL
UNION ALL SELECT 126, 'US' FROM DUAL
UNION ALL SELECT 127, 'US' FROM DUAL
UNION ALL SELECT 128, 'UK' FROM DUAL
UNION ALL SELECT 129, 'UK' FROM DUAL
UNION ALL SELECT 130, 'AU' FROM DUAL
UNION ALL SELECT 131, 'UK' FROM DUAL;

SELECT COUNT( DISTINCT CASENUMBER ) AS Num_Relevant_Cases
FROM   CASEDETAIL c
WHERE  CaseType = 'RelevantToThisQuestion'
AND    NOT EXISTS ( SELECT 1
                    FROM   LINKEDPEOPLE p
                           INNER JOIN LOCATION l
                           ON ( p.LinkedPerson = l.LinkedPerson )
                    WHERE  c.CaseNumber = p.CaseNumber
                    AND    l.Country = 'AU' )

| NUM_RELEVANT_CASES |
|--------------------|
|                  1 |

：

CREATE TABLE CASEDETAIL ( CaseNumber, CaseType ) AS
          SELECT 1, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 2, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 3, 'RelevantToThisQuestion' FROM DUAL
UNION ALL SELECT 4, 'NotRelevantToThisQuestion' FROM DUAL;

CREATE TABLE LINKEDPEOPLE ( CaseNumber, RelationshipType, LinkedPerson ) AS
          SELECT 1, 'Owner', 123 FROM DUAL
UNION ALL SELECT 1, 'Agent', 124 FROM DUAL
UNION ALL SELECT 1, 'Contact', 125 FROM DUAL
UNION ALL SELECT 2, 'Owner', 126 FROM DUAL
UNION ALL SELECT 2, 'Agent', 127 FROM DUAL
UNION ALL SELECT 2, 'Contact', 128 FROM DUAL
UNION ALL SELECT 3, 'Owner', 129 FROM DUAL
UNION ALL SELECT 3, 'Agent', 130 FROM DUAL
UNION ALL SELECT 3, 'Contact', 131 FROM DUAL;

CREATE TABLE LOCATION ( LinkedPerson, Country ) AS
          SELECT 123, 'AU' FROM DUAL
UNION ALL SELECT 124, 'UK' FROM DUAL
UNION ALL SELECT 125, 'UK' FROM DUAL
UNION ALL SELECT 126, 'US' FROM DUAL
UNION ALL SELECT 127, 'US' FROM DUAL
UNION ALL SELECT 128, 'UK' FROM DUAL
UNION ALL SELECT 129, 'UK' FROM DUAL
UNION ALL SELECT 130, 'AU' FROM DUAL
UNION ALL SELECT 131, 'UK' FROM DUAL;

SELECT COUNT( DISTINCT CASENUMBER ) AS Num_Relevant_Cases
FROM   CASEDETAIL c
WHERE  CaseType = 'RelevantToThisQuestion'
AND    NOT EXISTS ( SELECT 1
                    FROM   LINKEDPEOPLE p
                           INNER JOIN LOCATION l
                           ON ( p.LinkedPerson = l.LinkedPerson )
                    WHERE  c.CaseNumber = p.CaseNumber
                    AND    l.Country = 'AU' )

| NUM_RELEVANT_CASES |
|--------------------|
|                  1 |

对不起，我想巧妙地回答我的问题，实际上还有第三张表格，上面有国家信息。我会编辑。很抱歉，我试图通过简化我的问题场景来变得聪明，但实际上我过度简化了，使问题完全不同。谢谢，这就是我要找的。我所做的唯一更改是在子查询中反转C.CaseType条件。