SQL检查记录和日期时间之间的时差小时数

我需要在这个查询中添加一个额外的参数，并检查两条记录之间的时间是否至少为2小时。这是原始查询：

SELECT COUNT(Viewed) FROM [Views] WHERE userIP  = @userIP AND MessageID=@MessageID

我尝试添加第二个，如下所示：

SELECT COUNT(Viewed) FROM [Views] WHERE userIP = @userIP
AND MessageID=@MessageID
AND (@Now - dateTime)>2

SELECT COUNT(Viewed) FROM [Views] WHERE userIP = @userIP
AND MessageID=@MessageID
AND DATEDIFF(HOUR, @Now, dateTime)>2

也像这样：

SELECT COUNT(Viewed) FROM [Views] WHERE userIP = @userIP
AND MessageID=@MessageID
AND (@Now - dateTime)>2

SELECT COUNT(Viewed) FROM [Views] WHERE userIP = @userIP
AND MessageID=@MessageID
AND DATEDIFF(HOUR, @Now, dateTime)>2

@Now=日期时间Now，2015-01-26 09:08:28.183

dateTime=已发布记录2015-01-25 11:06:15.001表中的日期时间

但我没有得到结果。怎么做？

试试这个

DATEDIFF(SECOND, [dateTime], @Now) > (2 * 60 * 60)

---

这假设您的[dateTime]值都在过去。如果它们也可能在将来出现，那么将其包装在ABS中。

您将值错误地放在Datediff中，请使用@now作为最后一个参数

DECLARE @OMG Datetime
SET @OMG = '2015-01-25 11:06:15.001'

SELECT DATEDIFF(HOUR, @OMG, GETDATE())

IF (DATEDIFF(HOUR, @OMG, GETDATE()) > 2)
    BEGIN
        PRINT 'Yes'
    END
ELSE
    BEGIN
        PRINT 'NO'
    END 

DATEDIFFMINUTE，@Now>120