Sql ORACLE-逐行显示日期之间的间隔_Sql_Oracle

Sql ORACLE-逐行显示日期之间的间隔

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Sql ORACLE-逐行显示日期之间的间隔,sql,oracle,Sql,Oracle,下午好，请告诉我，如何一行一行地打破日期之间的间隔。我有一张桌子： with data as ( SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual UNION ALL SELECT 1 AS id,

下午好，请告诉我，如何一行一行地打破日期之间的间隔。我有一张桌子：

with data as (
SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 1 AS id, 235 AS status, to_date('25.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('27.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 1 AS id, 233 AS status, to_date('27.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('20.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('23.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('23.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('26.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('26.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual)

select * from data

我想得到结果：

with result_data as (
SELECT 1 AS id, 232 AS status, to_date('21.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 232 AS status, to_date('22.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 232 AS status, to_date('23.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 232 AS status, to_date('24.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 235 AS status, to_date('25.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 235 AS status, to_date('26.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 233 AS status, to_date('27.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 233 AS status, to_date('28.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('20.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('21.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('22.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('23.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('24.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('25.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('26.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('27.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('28.08.2019') AS dte FROM dual)

select * from result_data

我试着通过这个请求，但没有任何效果

SELECT trunc(t.start_dte) + level -1 dte FROM (select * from data 
where data.end_dte != to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss')) t
CONNECT BY level < trunc(t.end_dte) - trunc(t.start_dte) + 1

表中有很多行，有没有关于如何合理地做这件事的想法

好的，我现在明白了。这个过程称为数据加密。你可以用谷歌搜索

with data as (
SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 1 AS id, 235 AS status, to_date('25.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('27.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 1 AS id, 233 AS status, to_date('27.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('20.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('23.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('23.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('26.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('26.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual)
,ref_dates as ( select (select min(trunc(start_dte)) from data) + level dd from dual 
                                                                        connect by (select min(trunc(start_dte)) from data) + level 
                                                                            <= (select max(trunc(end_dte)) from data where end_dte != to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss')) )  
select id,status,dd vol from data partition by (status)
left join ref_dates x on (dd >=trunc(start_dte) and dd <= trunc(end_dte)   )
where 1=1
order by  status,dd

我已经在您的示例中对2999年结束的日期范围进行了注释，以使结果更加清楚：

with
maxdays
as
(select max( end_dte-start_dte )+1 days from 
    (SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 1 AS id, 235 AS status, to_date('25.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('27.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     --UNION ALL
     --SELECT 1 AS id, 233 AS status, to_date('27.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 2 AS id, 301 AS status, to_date('20.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('23.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 2 AS id, 264 AS status, to_date('23.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('26.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     --UNION ALL
     --SELECT 2 AS id, 259 AS status, to_date('26.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
    ) 
),
data
as
(select level-1 l from maxdays connect by level <= days )
select id,status,start_dte+l
  from data, (SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 1 AS id, 235 AS status, to_date('25.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('27.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     --UNION ALL
     --SELECT 1 AS id, 233 AS status, to_date('27.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 2 AS id, 301 AS status, to_date('20.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('23.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 2 AS id, 264 AS status, to_date('23.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('26.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     --UNION ALL
     --SELECT 2 AS id, 259 AS status, to_date('26.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
    )
 where l <= end_dte-start_dte
 order by 2,3,1;

我认为正确的答案并没有产生预期的结果

您可以尝试以下查询：

SQL> with data as (
  2  SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual UNION ALL
  3  SELECT 1 AS id, 235 AS status, to_date('25.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('27.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual UNION ALL
  4  SELECT 1 AS id, 233 AS status, to_date('27.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual UNION ALL
  5  SELECT 2 AS id, 301 AS status, to_date('20.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('23.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual UNION ALL
  6  SELECT 2 AS id, 264 AS status, to_date('23.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('26.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual UNION ALL
  7  SELECT 2 AS id, 259 AS status, to_date('26.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual)
  8  ,D AS (select ID, STATUS, TRUNC(start_dte) AS start_dte, TRUNC(end_dte) AS end_dte from data)
  9  SELECT
 10      ID,
 11      STATUS,
 12      START_DTE
 13  FROM
 14      (
 15          SELECT DISTINCT
 16              ID,
 17              STATUS,
 18              START_DTE + LEVEL - 1 AS START_DTE,
 19              END_DTE
 20          FROM
 21              D
 22          CONNECT BY
 23              LEVEL <= TRUNC(CASE
 24                  WHEN END_DTE = DATE '2999-12-31' THEN START_DTE + 1
 25                  ELSE END_DTE
 26              END) - START_DTE + 1
 27      )
 28  WHERE
 29      START_DTE != END_DTE
 30  ORDER BY
 31      ID,
 32      START_DTE
 33  ;

        ID     STATUS START_DTE
---------- ---------- ---------
         1        232 21-AUG-19
         1        232 22-AUG-19
         1        232 23-AUG-19
         1        232 24-AUG-19
         1        235 25-AUG-19
         1        235 26-AUG-19
         1        233 27-AUG-19
         1        233 28-AUG-19
         2        301 20-AUG-19
         2        301 21-AUG-19
         2        301 22-AUG-19

        ID     STATUS START_DTE
---------- ---------- ---------
         2        264 23-AUG-19
         2        264 24-AUG-19
         2        264 25-AUG-19
         2        259 26-AUG-19
         2        259 27-AUG-19

16 rows selected.

SQL>

干杯

ArkadiuszŁukasiewicz，用户希望在该日期之前以最大可用量生成缺少的行。@AnkitBajpai您说得对！有身份价值，太好了！这就是我需要的！非常感谢你。