Sql 如何从数据库中获取每个总数？

如何将查询写入下面的输出

在数据库中：

表1：

id Company_accountNo
1   123
2   235 
3   456

表2：

id cheque_no company_accnopky amount
1   258        1               100
2   963        1               200
3   147        2               500
4   148        3               800
5   852        2               300

如何获得这样的输出

Account_no   Total_Amount   No_of_Cheque
123           300               2
235           800               2
456           800               1

提前感谢..

请尝试：

SELECT a.Company_accountNo Account_no,
  SUM(b.amount) Total_Amount,
  COUNT(*) No_of_Cheque
FROM table1 a
LEFT JOIN table2 b
ON a.id=b.company_accnopky
GROUP BY a.Company_accountNo

select 
    a.Company_accountNo as Account_no, 
    SUM(b.amount) as Total_Amount, 
    COUNT(*) No_of_Cheque
from 
    tbl1 a inner join tbl2 b on a.id=b.company_accnopky
group by a.Company_accountNo

请尝试：

select 
    a.Company_accountNo as Account_no, 
    SUM(b.amount) as Total_Amount, 
    COUNT(*) No_of_Cheque
from 
    tbl1 a inner join tbl2 b on a.id=b.company_accnopky
group by a.Company_accountNo

请尝试：

select 
    a.Company_accountNo as Account_no, 
    SUM(b.amount) as Total_Amount, 
    COUNT(*) No_of_Cheque
from 
    tbl1 a inner join tbl2 b on a.id=b.company_accnopky
group by a.Company_accountNo

请尝试：

select 
    a.Company_accountNo as Account_no, 
    SUM(b.amount) as Total_Amount, 
    COUNT(*) No_of_Cheque
from 
    tbl1 a inner join tbl2 b on a.id=b.company_accnopky
group by a.Company_accountNo

试试这个：

select t1.Company_accountNo, SUM(t2.amount) as amount, count(t2.cheque_no) as cheque_no
from table1 t1, table2 t2
where t1.id=t2.company_accnopky
group by t1.Company_accountNo

试试这个：

select t1.Company_accountNo, SUM(t2.amount) as amount, count(t2.cheque_no) as cheque_no
from table1 t1, table2 t2
where t1.id=t2.company_accnopky
group by t1.Company_accountNo

试试这个：

select t1.Company_accountNo, SUM(t2.amount) as amount, count(t2.cheque_no) as cheque_no
from table1 t1, table2 t2
where t1.id=t2.company_accnopky
group by t1.Company_accountNo

试试这个：

select t1.Company_accountNo, SUM(t2.amount) as amount, count(t2.cheque_no) as cheque_no
from table1 t1, table2 t2
where t1.id=t2.company_accnopky
group by t1.Company_accountNo

试试这个：

SELECT
T1.Company_accountNo As Account_no,
sum(T2.Amount) As Total_Amount,
count(T1.Company_accountNo) AS No_of_Cheque  
FROM Table1 T1 Inner Join Table2 T2 ON T1.id = T2.company_accnopky 
Group By T1.Company_accountNo

我想你错过了小组，请尝试以下方法：

SELECT
T1.Company_accountNo As Account_no,
sum(T2.Amount) As Total_Amount,
count(T1.Company_accountNo) AS No_of_Cheque  
FROM Table1 T1 Inner Join Table2 T2 ON T1.id = T2.company_accnopky 
Group By T1.Company_accountNo

我想你错过了小组，请尝试以下方法：

SELECT
T1.Company_accountNo As Account_no,
sum(T2.Amount) As Total_Amount,
count(T1.Company_accountNo) AS No_of_Cheque  
FROM Table1 T1 Inner Join Table2 T2 ON T1.id = T2.company_accnopky 
Group By T1.Company_accountNo

我想你错过了小组，请尝试以下方法：

SELECT
T1.Company_accountNo As Account_no,
sum(T2.Amount) As Total_Amount,
count(T1.Company_accountNo) AS No_of_Cheque  
FROM Table1 T1 Inner Join Table2 T2 ON T1.id = T2.company_accnopky 
Group By T1.Company_accountNo

---

我认为您缺少了分组方式，您使用的是什么数据库管理系统？MSSQL/MySQL语法：

select company_acc_no，count（1）as no_of check，sum（amount）as total_amount from table 1内部连接table 2 on table 1.company_acc_np=table 2.company_acc_no group by company_acc_no

我想要hibernate查询它做错误查询语法例外你在用什么dbms？MSSQL/MySQL语法：

select company_acc_no，count（1）as no_of check，sum（amount）as total_amount from table 1内部连接table 2 on table 1.company_acc_np=table 2.company_acc_no group by company_acc_no

我想要hibernate查询它做错误查询语法例外你在用什么dbms？MSSQL/MySQL语法：

select company_acc_no，count（1）as no_of check，sum（amount）as total_amount from table 1内部连接table 2 on table 1.company_acc_np=table 2.company_acc_no group by company_acc_no

我想要hibernate查询它做错误查询语法例外你在用什么dbms？您还可以添加到目前为止您已经尝试过的内容吗？MSSQL/MySQL语法：

选择公司账户号，将（1）算作支票号，将（金额）算作表1中的总金额，将表1内部的表2连接到表1上。公司账户np=表2。公司账户号按公司分组账户号

我想要hibernate查询它使错误查询语法异常