SQL Server中以逗号分隔的值返回重复项
我正在编写一条语句,根据列的唯一ID值创建一个以逗号分隔的列值列表。某些ID具有多个电子邮件值 我有一个SQL Server中以逗号分隔的值返回重复项,sql,sql-server,ssrs-2008,Sql,Sql Server,Ssrs 2008,我正在编写一条语句,根据列的唯一ID值创建一个以逗号分隔的列值列表。某些ID具有多个电子邮件值 我有一个ID、电子邮件、摘要列 例如: ID | Summary | Email ---+---------+---------------- 1 | Hi | abc@gmail.com 1 | Hi | def@gmail.com 2 | good | xyz@gmail.com 通过阅读大量文章和堆栈溢出问题,我尝试了以下方法: SELECT STUF
ID、电子邮件、摘要列
例如:
ID | Summary | Email
---+---------+----------------
1 | Hi | abc@gmail.com
1 | Hi | def@gmail.com
2 | good | xyz@gmail.com
通过阅读大量文章和堆栈溢出问题,我尝试了以下方法:
SELECT
STUFF((SELECT ', ' + cr.Email AS [text()]
FROM Table1 cr1
WHERE cr1.Email = cr.Email
FOR XML PATH('')), 1, 1, '') AS List
FROM
Table1 cr
GROUP BY
cr.Email
上述查询的问题是,它向我显示了电子邮件,但它们都是重复的。例如:
ID | Summary | Email
---+---------+---------------------------------------------
1 | Hi | abc@gmail.com
1 | Hi | def@gmail.com, def@gmail.com, def@gmail.com
2 | good | xyz@gmail.com, xyz@gmail.com
所以我尝试了另一种方法
DECLARE @tmp VARCHAR(250)
SET @tmp = ''
SELECT @tmp = @tmp + cr.Email + ', '
FROM Table1 cr
SELECT
SUBSTRING(@tmp, 0, LEN(@tmp))
上述查询的问题是,它以逗号分隔的列表向我显示每封电子邮件。因此,每一行都有一个唯一的ID,其中包含所有的电子邮件
ID | Summary | Email
---+---------+--------------------------------------------
1 | Hi | abc@gmail.com, def@gmail.com, xyz@gmail.com
2 | good | abc@gmail.com, def@gmail.com, xyz@gmail.com
我正在寻找的解决方案应返回以下数据:
ID | Summary | Email
---+---------+------------------------------
1 | Hi | abc@gmail.com, def@gmail.com
2 | good | xyz@gmail.com
我能做些什么来改进我的查询,还是我完全朝着错误的方向前进 我想你只需要改变一下:
select
STUFF((SELECT ', ' + cr.Email AS [text()]
FROM Table1 cr1
where cr1.Email = cr.Email
FOR XML PATH('')), 1, 1, '') AS List
FROM Table1 cr
GROUP BY cr.Email
为此:
select
STUFF((SELECT ', ' + cr.Email AS [text()]
FROM Table1 cr1
where cr1.Email = cr.Email
FOR XML PATH('')), 1, 1, '') AS List
FROM Table1 cr
GROUP BY cr1.ID, cr1.Summary
似乎你应该关闭ID/摘要,而不是电子邮件
示例
Declare @YourTable Table ([ID] int,[Summary] varchar(50),[Email] varchar(50))
Insert Into @YourTable Values
(1,'Hi','abc@gmail.com')
,(1,'Hi','def@gmail.com')
,(2,'good','xyz@gmail.com')
Select A.ID
,A.Summary
,EMail = Stuff((Select Distinct ', ' +EMail From @YourTable Where ID=A.ID and Summary=A.Summary For XML Path ('')),1,2,'')
From @YourTable A
Group By ID,Summary
返回
ID Summary EMail
1 Hi abc@gmail.com, def@gmail.com
2 good xyz@gmail.com
看来你想要这个:
SELECT cr.ID,
cr.Summary,
STUFF((SELECT DISTINCT ', ' + cr1.Email
FROM Table1 cr1
WHERE cr1.ID = cr.ID
AND cr1.Summary = cr.Summary
FOR XML PATH('')), 1, 1, '') AS List
FROM Table1 cr
GROUP BY cr.ID, cr.Summary
内部的独立的
将防止同一封电子邮件在列表中多次出现。外部的分组依据
将根据其相应的ID对电子邮件列表进行分组
和摘要
,这不是您在初次尝试时通过电子邮件分组的问题吗?您应该按ID和摘要进行分组