Sql 如何在having子句下进行多次计数

一些样本数据：

Id    name    value    ref
1     ab      xy
2     aba     z
3     ab      xy
4     abc     def
5     gxr     mdy

我想做的是得到两个列，出现了不止一次 因此，将选择第1行和第3行

select name, value from table_x 
where value is not null group by name having count(name) >= 2 
and having count(value) >= 2;

---

被卡住了….

您的语法不正确<代码>按名称和值分组，然后检查计数>=2

select name, value 
from table_x 
where value is not null 
group by name, value 
having count(*) >= 2;

---

你的语法不正确<代码>按名称和值分组，然后检查计数>=2

select name, value 
from table_x 
where value is not null 
group by name, value 
having count(*) >= 2;

---

@如果您只关心查找多次出现的不同名称/值对，那么vkp的答案是正确的。但是，如果确实需要满足条件的单个行，请尝试以下操作：

SELECT  t1.Name, t1.[Value]
FROM    Table_X t1
JOIN
(
    SELECT  Name, [Value]
    FROM    Table_X
    where   [Value] IS NOT NULL
    GROUP   BY Name, [Value]
    HAVING  COUNT(1) >= 2
) t2 ON t1.Name = t2.Name AND t1.[Value] = t2.[Value]

---

@如果您只关心查找多次出现的不同名称/值对，那么vkp的答案是正确的。但是，如果确实需要满足条件的单个行，请尝试以下操作：

SELECT  t1.Name, t1.[Value]
FROM    Table_X t1
JOIN
(
    SELECT  Name, [Value]
    FROM    Table_X
    where   [Value] IS NOT NULL
    GROUP   BY Name, [Value]
    HAVING  COUNT(1) >= 2
) t2 ON t1.Name = t2.Name AND t1.[Value] = t2.[Value]