SQL Server查询总数
我需要一个查询,该查询与其他列合计SQL Server查询总数,sql,sql-server,pivot,Sql,Sql Server,Pivot,我需要一个查询,该查询与其他列合计 User sales amount date -------------------------------------- danny car 10.000 25/02/2016 danny moto 5.000 26/02/2016 danny car 10.000 25/03/2016 danny moto 5.000 26/03/2016 dann
User sales amount date
--------------------------------------
danny car 10.000 25/02/2016
danny moto 5.000 26/02/2016
danny car 10.000 25/03/2016
danny moto 5.000 26/03/2016
danny moto 5.000 26/03/2016
danny car 10.000 25/04/2016
danny moto 5.000 26/04/2016
danny car 10.000 25/05/2016
danny moto 5.000 26/05/2016
日期之间的结果按用户筛选,日期应按:
2016年3月1日至2016年3月31日
User Total moto car
------------------------------
danny 15.000 2 1
我需要什么查询?试试Pivot
SELECT * FROM
(
SELECT User,sales,amount,datename(month, date)
FROM YoyrTable
)A
PIVOT
(
SUM(amount)
FOR sales in ([car],[moto])
)B
另一种方法:
;WITH cte AS (
SELECT *
FROM (VALUES
('danny', 'car', 10.000, '2016-02-15'),
('danny', 'moto', 5.000, '2016-02-26'),
('danny', 'car', 10.000, '2016-03-25'),
('danny', 'moto', 5.000, '2016-03-26'),
('danny', 'moto', 5.000, '2016-03-26'),
('danny', 'car', 10.000, '2016-04-25'),
('danny', 'moto', 5.000, '2016-04-26'),
('danny', 'car', 10.000, '2016-05-25'),
('danny', 'moto', 5.000, '2016-05-26')
) as t([User], sales, amount, [date])
)
SELECT [user],
SUM(amount) as Total,
SUM(CASE WHEN sales = 'moto' THEN 1 ELSE 0 END) as moto,
SUM(CASE WHEN sales = 'car' THEN 1 ELSE 0 END) as car,
DATENAME(Month,[date]) as [date]
FROM cte
GROUP BY [user], DATENAME(Month,[date]),DATEPART(Month,[date]), DATEPART(Year,[date])
ORDER BY DATEPART(Month,[date]), DATEPART(Year,[date])
输出:
user Total moto car date
danny 15.000 1 1 February
danny 20.000 2 1 March
danny 15.000 1 1 April
danny 15.000 1 1 May
在查询中,将您的表名改为
cte实际的PIVOT
应该是什么样子
SELECT [User],
Total,
[moto],
[car],
[date]
FROM
(
SELECT [User],
sales,
DATENAME(MONTH,date) [date],
SUM(amount) OVER (PARTITION BY [User], DATENAME(MONTH,date)) [Total]
FROM cte
) T
PIVOT
(
COUNT(sales)
FOR sales IN ([car], [moto])
) p
@gofr1的答案应该表现得更好。首先向我们展示您迄今为止的努力!你试过什么?你被困在哪里?我们会提供帮助,但我们不会只为您编写全部代码!