使用GROUPBY子句的SQL联接查询？ 输出：

这个代码怎么了？

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我想要所有的cloumn（e.employee\u id，e.last\u name，e.salary，e.department\u id，d.department\u name）和d.department\u id，d.department\u name）是否可能？

您只能按子句选择分组中的列。

作为按子句分组的规则，您应该包括不属于聚合的所有列。在这种情况下，您需要包括GROUP BY子句中的所有列

SQL> SELECT e.employee_id, e.last_name, e.salary, e.department_id, d.department_name
  2  FROM employees e, departments d
  3  WHERE e.department_id = d.department_id
  4  GROUP BY d.department_id, d.department_name;
SELECT e.employee_id, e.last_name, e.salary, e.department_id, d.department_name
       *
ERROR at line 1:
ORA-00979: not a GROUP BY expression

或

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请参阅此代码。这将是工作

SELECT e.employee_id, e.last_name, SUM(e.salary), e.department_id, d.department_name
FROM employees e, departments d
WHERE e.department_id = d.department_id
GROUP BY e.employee_id, e.last_name, e.department_id, d.department_name;

或

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你得到了什么输出？您的预期输出是什么？请选择e.员工id、e.姓氏、e.薪资、e.部门id、d.部门名称*第1行错误：ORA-00979:不是按表达式分组我希望所有列都作为输出并仅按分组（d.部门id、d.部门名称）。。。可能吗？不可能在ANSI-92 SQL标准中（20多年前），旧样式的逗号分隔表列表样式被正确的ANSI

JOIN

语法所取代，不鼓励使用它

SELECT e.employee_id, e.last_name, e.salary, e.department_id, d.department_name
FROM employees e, departments d
WHERE e.department_id = d.department_id
GROUP BY e.employee_id, e.last_name, e.salary, e.department_id, d.department_name;

SELECT e.employee_id, e.last_name, SUM(e.salary), e.department_id, d.department_name
FROM employees e, departments d
WHERE e.department_id = d.department_id
GROUP BY e.employee_id, e.last_name, e.department_id, d.department_name;

SELECT e.id, e.name, e.salary, e.did, d.dname
FROM [dbo].[Table_1] e join [dbo].[Table_2] d
on e.did = d.did
GROUP BY e.id, e.name, e.salary, e.did, d.dname;

SELECT e.id, e.name, e.salary, e.did, d.dname
FROM [dbo].[Table_1] e , [dbo].[Table_2] d
WHERE  e.did = d.did
GROUP BY e.id, e.name, e.salary, e.did, d.dname;